ios - 当 iPhone/iPad 上的设备方向发生变化时如何在 Swift 中处理弹出窗口

Question

我正在 Swift 中使用 popoverPresentationController 创建一个弹出框。它第一次显示正常，但当我旋转设备时，它改变了它的源位置。
无论方向如何，我怎样才能让它停留在它的原始源点？

我做的代码。

@IBAction func btn_popover_click(发件人:UIButton){

    let menuViewController = PopoverViewController()
    menuViewController.modalPresentationStyle = UIModalPresentationStyle.Popover
    menuViewController.preferredContentSize = CGSizeMake(50, 100) // Size of popover.

    popoverMenuViewController = menuViewController.popoverPresentationController
    popoverMenuViewController?.permittedArrowDirections = .Any
    popoverMenuViewController?.delegate = self
    popoverMenuViewController?.sourceView = sender.superview
    popoverMenuViewController?.sourceRect = sender.frame
    presentViewController(
        menuViewController,
        animated: true,
        completion: nil)
}

Answer 1

swift 3

确保呈现弹出窗口的 View Controller 符合 UIPopoverPresentationControllerDelegate。

例子:

class MyViewContoller: UIVIewContoller, UIPUIPopoverPresentationControllerDelegate 
{

// your code...

// MARK: UIPopoverPresentationControllerDelegate Methods

func popoverPresentationController(_ popoverPresentationController: UIPopoverPresentationController, willRepositionPopoverTo rect: UnsafeMutablePointer<CGRect>, in view: AutoreleasingUnsafeMutablePointer<UIView>) {
    let viewFrame = popoverPresentationController.presentingViewController.view.frame
    let deltaX = viewFrame.height - rect.pointee.midX
    rect.pointee = CGRect(x: viewFrame.width - deltaX, y: rect.pointee.maxY, width: 0, height: 0)
}