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mysql - 如何提高嵌套集模型中数千个插入的速度?

转载 作者:行者123 更新时间:2023-11-29 02:06:20 25 4
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我正在使用 MySQL。我想插入 100.000 个属于具有不同级别(root_id、lft、rgt、级别)的嵌套集模型的位置。如果我不必担心树,我会做一个批量插入;但在这种情况下,我必须按此顺序对每个对象执行 3 次查询:

foreach ( $places as $place )
{
# get parent place from $ancestor_array ( woeid => ids )
$parent = $ancestors[:parent_woeid]

update place set lft = lft + 2 where root_id = :root_id and lft >= :obj_lft;
update place set rgt = rgt + 2 where root_id = :root_id and rgt >= :obj_lft;
insert into place (..., root_id, lft, rgt, level, ...) values (..., :obj_root_id, :obj_lft, :obj_rgt, :obj_level, ...);

...
}

这需要很长时间...所以是时候变得更聪明了。这就是我的想法:

foreach ( $places as $place )
{
# get parent place from $ancestor_array ( woeid => ids )
$parent = $ancestors[:parent_woeid]

$new_admins[] = array('parent_woeid' => :parent_woeid, ...data place....)
$woeids[] = :parent_woeid;
}

# lock + bulk insert of $new_admins with lft=rgt=level=root_id= null + unlock
insert into place (...) values (...), (...), (...), ...., (...)

# get ids of those places
select from place where woeid in(:array_woeids)

# lock + bulk update with 3 updates per place + unlock
update place set lft= lft + 2 where root_id = :root_id and lft >= :obj_lft;
update place set rgt = rgt + 2 where root_id = :root_id and rgt >= :obj_lft;
update place set lft=:obj_lft, rgt=:obj_rgt where id=:id

# i have to update the ancestors lft & rgt values on the $ancestors_array,
# because we have them "cached" in the array in order to avoid doing a
# select per inserted place.

你怎么看?你会怎么做?您是否会将所有插入和更新保存到文件中并使用 LOAD DATA INFILE 语法而不是此选项?

我还缺少其他选项吗?

非常感谢!

最佳答案

仅插入项目并仅在插入所有项目时才重新计算所有 lft/rgt 索引是否更有效?

然而,要做到这一点,您必须知道每个项目的父 ID,这样您就有了索引的基础。我个人成功地将 lft + lrg + parentId 与每个数据项保持在一起,它使维护变得更加容易(您可以随时进行简单的重新计算/完整性检查)。

关于mysql - 如何提高嵌套集模型中数千个插入的速度?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5352698/

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