ios - 根据用户决定取消选中开关

Question

我正在构建一个应用程序，当用户启用开关时，它会请求用户允许发布通知。我正在使用这段代码:

- (IBAction)mySwitchValueChanged:(id)sender {
if ([UIApplication instancesRespondToSelector:@selector(registerUserNotificationSettings:)]){
    [[UIApplication sharedApplication] registerUserNotificationSettings:[UIUserNotificationSettings settingsForTypes:UIUserNotificationTypeAlert|UIUserNotificationTypeBadge|UIUserNotificationTypeSound categories:nil]]; // ask the user for permission
}

if ([[UIApplication sharedApplication] respondsToSelector:@selector(currentUserNotificationSettings)]) { // Check it's iOS 8 and above
    UIUserNotificationSettings *grantedSettings = [[UIApplication sharedApplication] currentUserNotificationSettings];
    if (grantedSettings.types != UIUserNotificationTypeNone)
    {
        // Accepted
    } else
    {
        [self.mySwitch setOn:NO]; // Declined
    }
}
}

所需的行为如下:

• 用户滑动切换
• 警报请求许可
• 代码等待用户决定
• 无论我在已接受的地方编写什么代码，都执行//或禁用开关。

当前的行为是让代码一次性跑完，不等用户决定。我如何更改它以获得所需的行为？

谢谢!

Answer 1

注意:这是解决方法

一旦您调用此方法:- [UIApplication sharedApplication] registerUserNotificationSettings 并且用户授予该应用的推送通知，然后 AppDelegate 中的 didRegisterForRemoteNotificationsWithDeviceToken 将被解雇，

    - (void)application:(UIApplication *)application didRegisterForRemoteNotificationsWithDeviceToken:(NSData *)deviceToken
{
  //call a notification when user granted Push Notifiaction 
   [[NSNotificationCenter defaultCenter] 
    postNotificationName:@"PushNotificationSuccess" 
    object:self];

}

所以您必须做的是，您可以从上述方法调用 NSNotification，以相应地更新 UI。

- (void)updateUIOnNotification:(NSNotification *) notification
{

            // Accepted
   }