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php - 如何将图像从 Android 应用程序上传到网络服务器到特定文件夹

转载 作者:行者123 更新时间:2023-11-29 02:01:25 24 4
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如何将图像从android移动到网络服务器上的指定文件夹

这是我的安卓代码

package com.example.bitmaptest;

import java.io.ByteArrayOutputStream;
import java.io.InputStream;
import java.util.ArrayList;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;

import android.app.Activity;
import android.graphics.Bitmap;
import android.graphics.BitmapFactory;
import android.os.Bundle;
import android.util.Base64;
import android.util.Log;

public class Upload extends Activity {
InputStream is;

@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Bitmap bitmapOrg=BitmapFactory.decodeResource(getResources(),R.drawable.a1);
ByteArrayOutputStream bao = new ByteArrayOutputStream();
bitmapOrg.compress(Bitmap.CompressFormat.JPEG, 90, bao);
byte[] ba = bao.toByteArray();
String ba1 = Base64.encodeToString(ba, 0);
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("image", ba1));

try {

HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(
"http://0.0.0.7:80/android/base.php");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
} catch (Exception e) {
Log.e("log_tag", "Error in http connection " + e.toString());
}

}
}

这是我的 php 脚本

$uploadedFile = $_FILES['image']['name'];

$uploadedType = $_FILES['image']['type'];

$temp = $_FILES['image']['tmp_name'];

$error = $_FILES['image']['error'];

if ($error > 0) {
die("File could not be uploaded. $error");
}
else {
move_uploaded_file($temp, "images/".$uploadedFile);
echo "Upload Complete. ".$uploadedType;
}

当我在 android 中发送时,httppost 工作,它显示在 wireshark 中,但文件是空的。没有图像。

最佳答案

doFileUpload 函数:

private void doFileUpload(){
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String exsistingFileName = "/sdcard/six.3gp";
// Is this the place are you doing something wrong.
String lineEnd = "\r\n";
String twoHyphens = "--";
String boundary = "*****";
int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1*1024*1024;
String urlString = "http://192.168.1.5/upload.php";
try
{
Log.e("MediaPlayer","Inside second Method");
FileInputStream fileInputStream = new FileInputStream(new File(exsistingFileName) );
URL url = new URL(urlString);
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true);
// Allow Outputs
conn.setDoOutput(true);
// Don't use a cached copy.
conn.setUseCaches(false);
// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("Content-Type", "multipart/form-data;boundary="+boundary);
dos = new DataOutputStream( conn.getOutputStream() );
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\"" + exsistingFileName +"\"" + lineEnd);
dos.writeBytes(lineEnd);
Log.e("MediaPlayer","Headers are written");
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0)
{
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
BufferedReader in = new BufferedReader(new InputStreamReader(conn.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null)
tv.append(inputLine);
// close streams
Log.e("MediaPlayer","File is written");
fileInputStream.close();
dos.flush();
dos.close();
}
catch (MalformedURLException ex)
{
Log.e("MediaPlayer", "error: " + ex.getMessage(), ex);
}
catch (IOException ioe)
{
Log.e("MediaPlayer", "error: " + ioe.getMessage(), ioe);
}

//------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream ( conn.getInputStream() );
String str;
while (( str = inStream.readLine()) != null)
{
Log.e("MediaPlayer","Server Response"+str);
}
/*while((str = inStream.readLine()) !=null ){

}*/
inStream.close();
}
catch (IOException ioex){
Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex);
}
}

关于php - 如何将图像从 Android 应用程序上传到网络服务器到特定文件夹,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12525725/

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