php - 将数据从android发布到PHP

Question

我已经使用这个论坛很长时间了，首先，我想说谢谢你的帮助我很多次。这是我第一次找不到答案，这让我很疯狂......

我正在尝试编写一个 super 简单的应用程序，它从数据库获取数据/将数据发布到数据库中。问题是，我无法发布数据(get 没问题)。我正在使用一个 php 文件，它应该从 Android 设备获取数据，并将其发送到数据库。首先，我无法将其发布到我的 php 文件中。我已经尝试了所有(我知道的)。

PHP 文件-

$test=$_POST['v']; print $_POST['v']; 

Java 文件-

public void postData() 抛出 ClientProtocolException, IOException {

    // Create a new HttpClient and Post Header
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost post = new HttpPost("https://www.myweb.coom/test.php");

    try {
        // Add your data
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);
        nameValuePairs.add(new BasicNameValuePair("v", "123"));
        post.setEntity(new UrlEncodedFormEntity(nameValuePairs));

        // Execute HTTP Post Request
        httpclient.execute(post);

    } catch (ClientProtocolException e) {
        // TODO Auto-generated catch block
    } catch (IOException e) {
        // TODO Auto-generated catch block
    }
}

当我输入 Log.* 时，它告诉我一切正常。 PHP 似乎没有获取任何数据...

编辑异步任务-----公共(public)类上传扩展 AsyncTask{

@Override
protected String doInBackground(String... params) {
    try {
        JSONObject json = new JSONObject();
        json.put("UserName", "test2");
        json.put("FullName", "1234567");
        HttpParams httpParams = new BasicHttpParams();
        HttpConnectionParams.setConnectionTimeout(httpParams,
                10000);
        HttpConnectionParams.setSoTimeout(httpParams, 10000);
        HttpClient client = new DefaultHttpClient(httpParams);
        //

        String url = "http://my WAMP server/test.php"+ 
                            "json={\"UserName\":1,\"FullName\":2}";

        HttpPost request = new HttpPost(url);
        request.setEntity(new ByteArrayEntity(json.toString().getBytes(
                "UTF8")));
        request.setHeader("json", json.toString());
        HttpResponse response = client.execute(request);
        HttpEntity entity = response.getEntity();
        // If the response does not enclose an entity, there is no need
        if (entity != null) {
            InputStream instream = entity.getContent();

            String result = "gr8 Success";
            Log.i("Read from server", result);

        }
    } catch (Throwable t) {
        Log.e("Request failed: " ,"ERR"+ t.toString());
    }

}

MainActivity-

public void postData(View v) { //starts on button click

    if(upload!=null){
        if(upload.getStatus()!= AsyncTask.Status.FINISHED){
            Log.d("postData","no need to start AsyncTask");
            return;
        }

    }
    upload= new Upload();
    upload.execute();
    Log.i("Async", "Starting...");

}

PHP- $json=$_GET ['json']; $obj = json_decode($json);

               $posts = array(1);
               header('Content-type: application/json');
                 echo json_encode(array('posts'=>$posts));

Answer 1

您的 URL 域包含 2 个“o”。你应该写 https://www.myweb.com/test.php , 不是 https://www.myweb.coom/test.php