gpt4 book ai didi

Android:如何在可移动图像上绘制矩形,使绘制的矩形也随图像一起移动?

转载 作者:行者123 更新时间:2023-11-29 01:50:50 26 4
gpt4 key购买 nike

我有一个可以在整个屏幕上移动的图像。现在,我想在此图像上绘制一个矩形,这样当我移动图像时,绘制在图像上的矩形也会移动。目前我可以在包含图像的 SurfaceView 上绘制矩形而不是在图像上。我当前的代码如下。

public class MainActivity extends Activity {

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);


int w=getWindowManager().getDefaultDisplay().getWidth()-25;
int h=getWindowManager().getDefaultDisplay().getHeight()-25;

MySurfaceView mySurface=new MySurfaceView(this,w,h);
setContentView(mySurface);
}
}

我有一个名为 MySurfaceView.java 的类

public class MySurfaceView extends SurfaceView implements SurfaceHolder.Callback {

private Bitmap bitmap ;
private MyThread thread;
private int x=20,y=20;int width,height;

public MySurfaceView(Context context,int w,int h) {
super(context);

width=w;
height=h;
thread=new MyThread(getHolder(),this);
getHolder().addCallback(this);
setFocusable(true);
}

@Override
public void onDraw(Canvas canvas) {
super.onDraw(canvas);

bitmap =BitmapFactory.decodeResource(getResources(), R.drawable.my_pic);
canvas.drawColor(Color.BLUE);//To make background
canvas.drawBitmap(bitmap,x-(bitmap.getWidth()/2),y-(bitmap.getHeight()/2),null);


Paint paintShape = new Paint();
paintShape.setColor(Color.BLACK);
paintShape.setStyle(Paint.Style.STROKE);

Rect myRectangle = new Rect();
myRectangle.set(0, 100, canvas.getWidth()/4, canvas.getHeight()/4);

canvas.drawRect(myRectangle, paintShape);


}

@Override
public boolean onTouchEvent(MotionEvent event) {

x=(int)event.getX();
y=(int)event.getY();

if(x<25)
x=25;
if(x> width)
x=width;
if(y <25)
y=25;
if(y > 405)
y=405;
return true;
}

@Override
public void surfaceChanged(SurfaceHolder holder, int format, int width,int height) {
// TODO Auto-generated method stub

}

@Override
public void surfaceCreated(SurfaceHolder holder) {

thread.startrun(true);
thread.start();

}

@Override
public void surfaceDestroyed(SurfaceHolder holder) {


thread.startrun(false);
thread.stop();

}

public class MyThread extends Thread{

private SurfaceHolder msurfaceHolder;
private MySurfaceView mSurfaceView;
private boolean mrun =false;

public MyThread(SurfaceHolder holder, MySurfaceView mSurfaceView) {

this.msurfaceHolder = holder;
this.mSurfaceView=mSurfaceView;
}

public void startrun(boolean run) {

mrun=run;
}

@SuppressLint("WrongCall")
@Override
public void run() {

super.run();
Canvas canvas;
while (mrun) {
canvas=null;
try {
canvas = msurfaceHolder.lockCanvas(null);
synchronized (msurfaceHolder) {
mSurfaceView.onDraw(canvas);
}
} finally {
if (canvas != null) {
msurfaceHolder.unlockCanvasAndPost(canvas);
}
}
}
}
}
}

有人可以帮助我改进我的代码以适应上述所需的任务吗?谢谢!

最佳答案

好吧,我想出了自己的办法。这只是上述代码的一个小改动,这是必要的。定义矩形相对于因触摸事件获得的 x 和 y 的坐标就足够了。例如,您可以执行以下操作:

myRectangle.set(x-50, y-50, x+50, y+50);

其余的将自动处理。

关于Android:如何在可移动图像上绘制矩形,使绘制的矩形也随图像一起移动?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18192205/

26 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com