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Php Mysql 存储过程 IN OUT

转载 作者:行者123 更新时间:2023-11-29 01:33:16 25 4
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案例:存储过程如下所示:

DROP PROCEDURE IF EXISTS `XofferCommon`.`getCdpc`;<br>
DELIMITER $$<br>
CREATE PROCEDURE `XofferCommon`.`getCdpc` (IN in_city_ID INT, OUT out_country_id INT, OUT out_district_id INT, OUT out_provence_id INT, OUT out_city_id INT)<br>
BEGIN<br>
DECLARE city_ID INT DEFAULT in_city_ID;<br>
SELECT t.Id, d.Id, p.Id, c.Id INTO out_country_id, out_district_id, out_provence_id, out_city_id FROM ((tblCity AS c INNER JOIN tblProvence AS p ON c.tblProvence_Id = p.ID) INNER JOIN tblDistrict AS d ON p.tblDistrict_Id = d.ID) INNER JOIN tblCountry AS t ON -d.tblCountry_Id = t.ID WHERE c.id = city_ID;<br>
END$$<br>
DELIMITER ;<br><br>
<br>---------------------------------------------------
Input: int referring to in_city_id<br>
Output: 4 x int country district provence and city id's<br>
---------------------------------------------------<br>

Php:我想调用过程并将返回的 4 个对象存储到 4 个变量中

if ($res = $mysqli->query( 'CALL getCdpc(1321,@co,@di,@pr,@ci);SELECT @co,@di,@pr,@ci'))<br>
{<br>
while($row = $res->fetch_object())<br>
{<br>
print($row);<br>
}<br>
$res->close();<br>
}<br>
else<br>
{<br>
print "<br> no result given <br>";<br>
}<br>
<br>
Result:<br>
-------<br>

我总是返回零行

<br>
<br>
More info:<br>
----------<br>
in mysql sql the results get returned when I do:<br>
->call xoffercommon.getCdpc(1321,@co,@di,@pr,@ci);<br>
->select @co,@di,@pr,@ci;<br>
=> @co @di @pr @ci<br>
1 2 3 4<br>
<br>
Question:<br>
---------<br>

我是否必须运行 2 个查询,一个过程调用和一个结果选择?
有没有办法在一行中运行它?
...请帮助我找不到解决问题的方法,已经尝试在过程中返回,但这只允许在函数中使用。已经过去 2 周了……通过阅读/反复试验学到了很多东西 ;-),但是没有什么能破解这个案子……

最佳答案

当您可以简单地返回一个结果集时,不确定为什么要传递 4 个变量。这也可以避免您每次想要扩展输出数据时都必须更改存储过程接口(interface)。

MySQL

drop procedure if exists XofferCommon.getCdpc;

delimiter #

create procedure XofferCommon.getCdpc
(
in p_city_id int unsigned
)
begin
select
t.Id as country_id,
d.Id as district_id,
p.Id as provence_id,
c.Id as city_id
from
tblCity c
inner join tblProvence p on c.tblProvence_Id = p.Id
inner join tblDistrict d on p.tblDistrict_Id = d.Id
inner join tblCountry t on d.tblCountry_Id = t.Id
where
c.Id = p_city_id;
end#

delimiter ;

PHP

<?php

ob_start();

try
{
$db = new mysqli("localhost", "foo_dbo", "pass", "foo_db", 3306);

if ($db->connect_errno)
throw new exception(sprintf("Could not connect: %s", $db->connect_error));

$sqlCmd = sprintf("call getCdpc(%d)", 1);

$result = $db->query($sqlCmd);

if(!$result) throw new exception(sprintf("Invalid query : %s", $sqlCmd));

if($result->num_rows <= 0){
echo "no records found !";
}
else{
$row = $result->fetch_assoc();
echo sprintf("country_id = %d district_id = %d, provence_id = %d, city_id = %d",
$row["country_id"],$row["district_id"],$row["provence_id"],$row["city_id"]);
}
$db->next_result();
$result->close();
}
catch(exception $ex)
{
ob_clean();
echo sprintf("zomg borked - %s", $ex->getMessage());
}

if(!$db->connect_errno) $db->close();
ob_end_flush();
?>

在清理模式时也值得您这样做,这样您的键就有了更合适的整数数据类型(并非所有内容都是 4 字节的带符号整数),并避免您似乎为同一件事选择的字段名称的混合,即Id、ID、City_Id、City_ID 等,这将避免所有不必要的别名!

http://dev.mysql.com/doc/refman/5.0/en/numeric-types.html

MySQL 修改后的模式

  • 删除了 tbl 表名前缀
  • 为您的键选择更合适的整数数据类型
  • 重命名了您的关键字段,使它们保持一致,即 city_id

表格

drop table if exists country;
create table country
(
country_id tinyint unsigned not null auto_increment primary key -- 0 to 255 countries;
)
engine=innodb;

drop table if exists district;
create table district
(
district_id smallint unsigned not null auto_increment primary key, -- 0 to 65535 districts
country_id tinyint unsigned not null
)
engine=innodb;

drop table if exists provence;
create table provence
(
provence_id smallint unsigned not null auto_increment primary key, - 0 to 65535 provences
district_id smallint unsigned not null
)
engine=innodb;

drop table if exists city;
create table city
(
city_id mediumint unsigned not null auto_increment primary key, - 0 to 16777215 cities
provence_id smallint unsigned not null
)
engine=innodb;

存储过程

drop procedure if exists getCdpc;

delimiter #

create procedure getCdpc
(
in p_city_id mediumint unsigned
)
begin
select
t.country_id,
d.district_id,
p.provence_id,
c.city_id
from
city c
inner join provence p on c.provence_id = p.provence_id
inner join district d on p.district_id = d.district_id
inner join country t on d.country_id = t.country_id
where
c.city_id = p_city_id;
end#

delimiter ;

希望这有帮助:)

关于Php Mysql 存储过程 IN OUT,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/4942035/

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