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MySQL:如何将列别名与特定的 JOIN 子句相关联

转载 作者:行者123 更新时间:2023-11-29 01:30:40 25 4
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我的查询使用几个 LEFT JOIN 从几个表中提取结果。它目前工作正常。但是,我现在必须从同一个表列中获取两个不同的字段(但匹配不同的条件)。我不知道如何确保从正确的 LEFT JOIN 分配正确的列别名。有道理吗?

举个例子...

SELECT table1.user_id, table2.value AS school, table2.value AS language  FROM table1  
LEFT JOIN table2 ON table2.user_id = table1.user_id AND table2.key = 'school'
LEFT JOIN table2 ON table2.user_id = table1.user_id AND table2.key = 'language'

我需要具有相应 JOIN 的列别名。我该怎么做?

作为引用,这是我的原始查询(没有辅助 JOIN):

SELECT wsat_ib.user_id, wpjb_resume.id resume_id, wpjb_resume.firstname, wpjb_resume.lastname, 
wsat_ib.overall_score, wsat_ib.account_score, wsat_ib.econ_score, wsat_ib.math_score,
wsat_ib.logic_score, wsat_ib.fsanaly_score, wsat_ib.corpval_score, wsat_ib.end_time,
GROUP_CONCAT(DISTINCT wp_usermeta.meta_value) AS target_employers, wpjb_field_value.value AS school,
GROUP_CONCAT(wpjb_application.job_id) AS applications FROM `wsat_ib`
LEFT JOIN wp_usermeta ON wsat_ib.user_id = wp_usermeta.user_id
LEFT JOIN wpjb_resume ON wsat_ib.user_id = wpjb_resume.user_id
LEFT JOIN wpjb_field_value ON wpjb_resume.id=wpjb_field_value.job_id AND wpjb_field_value.field_id=3
LEFT JOIN wpjb_application ON wpjb_application.user_id = wsat_ib.user_id
WHERE (wp_usermeta.meta_key = 'target_employer' AND (wp_usermeta.meta_value = 'public' OR wp_usermeta.meta_value=1523) AND wpjb_resume.is_active =1) AND (wpjb_resume.firstname='Xu' OR wpjb_resume.lastname='Xu')
GROUP BY wsat_ib.user_id, resume_id, wpjb_resume.firstname, wpjb_resume.lastname, wsat_ib.overall_score, wsat_ib.account_score, wsat_ib.econ_score, wsat_ib.math_score, wsat_ib.logic_score, wsat_ib.fsanaly_score, wsat_ib.corpval_score, wsat_ib.end_time, wpjb_field_value.value
ORDER BY overall_score DESC LIMIT 0, 20;

这是我在实现以下解决方案时的早期尝试。我已将 AS school 添加到 JOIN 子句,但尚未为该表添加第二个 JOIN。由于某种原因,此版本不返回任何结果。

SELECT wsat_ib.user_id, wpjb_resume.id resume_id, wpjb_resume.firstname, wpjb_resume.lastname, 
wsat_ib.overall_score, wsat_ib.account_score, wsat_ib.econ_score, wsat_ib.math_score,
wsat_ib.logic_score, wsat_ib.fsanaly_score, wsat_ib.corpval_score, wsat_ib.end_time,
GROUP_CONCAT(DISTINCT wp_usermeta.meta_value) AS target_employers, wpjb_field_value.value AS school,
GROUP_CONCAT(wpjb_application.job_id) AS applications FROM `wsat_ib`
LEFT JOIN wp_usermeta ON wsat_ib.user_id = wp_usermeta.user_id
LEFT JOIN wpjb_resume ON wsat_ib.user_id = wpjb_resume.user_id
LEFT JOIN wpjb_field_value AS school ON wpjb_resume.id=wpjb_field_value.job_id AND wpjb_field_value.field_id=3
LEFT JOIN wpjb_application ON wpjb_application.user_id = wsat_ib.user_id
WHERE (wp_usermeta.meta_key = 'target_employer' AND (wp_usermeta.meta_value = 'public' OR wp_usermeta.meta_value=1523) AND wpjb_resume.is_active =1) AND (wpjb_resume.firstname='Xu' OR wpjb_resume.lastname='Xu')
GROUP BY wsat_ib.user_id, resume_id, wpjb_resume.firstname, wpjb_resume.lastname, wsat_ib.overall_score, wsat_ib.account_score, wsat_ib.econ_score, wsat_ib.math_score, wsat_ib.logic_score, wsat_ib.fsanaly_score, wsat_ib.corpval_score, wsat_ib.end_time, wpjb_field_value.value
ORDER BY overall_score DESC LIMIT 0, 20;

最佳答案

您还需要为表设置别名,而不仅仅是列。

SELECT table1.user_id, schools.value AS school, languages.value AS language
FROM table1
LEFT JOIN table2 AS schools ON schools.user_id = table1.user_id
AND schools.key = 'school'
LEFT JOIN table2 AS languages ON languages.user_id = table1.user_id
AND languages.key = 'language'

如果一个表在查询中出现不止一次,您可以将每次出现都视为一个实例。您需要为表的每个实例命名以消除歧义。

关于MySQL:如何将列别名与特定的 JOIN 子句相关联,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14183817/

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