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mysql - 如何在 MySQL 中获取结果(行)数?

转载 作者:行者123 更新时间:2023-11-29 01:28:43 26 4
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通常下面的查询只给我一个结果(行)。

SELECT
`s`.`FIRMA_UNVANI` AS `FIRMA_UNVANI`,
`s`.`RECNO` AS `RECNO`,
`s`.`BOLGE` AS `BOLGE`,
`s`.`BOLGE_NO` AS `BOLGE_NO`,
`s`.`DURUM` AS `DURUM`,
l.ILCE,
IL.SEHIR,
count(i.recno) AS NUMBER_OF_WORKS
FROM
`SERVISLER` `s`
LEFT JOIN KULLANICI k ON (s.BOLGE = k.KULLANICI)
LEFT JOIN kullanici_cihaz kc ON (k.RECNO = kc.KUL_RECNO)
LEFT JOIN servisler_ilceler c ON (s.RECNO = c.SER_RECNO)
INNER JOIN ILCE l ON (l.RECNO = c.ILCE_RECNO)
INNER JOIN IL ON (IL.ID = l.ILID)
LEFT JOIN ISEMRI i ON (
i.bolge = s.bolge_no
AND i.`SERVIS_DURUMU` = 1
)
WHERE
1 = 1
GROUP BY
s.BOLGE
ORDER BY
IS_SAYISI
LIMIT 0,
15

我只得到一个结果

+----------------+-------+------+---------+------+-----+----------+-----------------+
|FIRMA_UNVANI |RECNO |BOLGE |BOLGE_NO |DURUM |ILCE | SEHIR | NUMBER_OF_WORKS |
+----------------+-------+------+---------+------+-----+----------+-----------------+
|Pirana |2501 |Tekkt |58 |-1 |NT |Istanbul |1428 |
+----------------+-------+------+---------+------+-----+----------+-----------------+

这里的关键是RECNO。

我要统计结果:

SELECT
count(0) AS _count
FROM
`SERVISLER` `s`
LEFT JOIN KULLANICI k ON (s.BOLGE = k.KULLANICI)
LEFT JOIN kullanici_cihaz kc ON (k.RECNO = kc.KUL_RECNO)
LEFT JOIN servisler_ilceler c ON (s.RECNO = c.SER_RECNO)
INNER JOIN ILCE l ON (l.RECNO = c.ILCE_RECNO)
INNER JOIN IL ON (IL.ID = l.ILID)
LEFT JOIN ISEMRI i ON (
i.bolge = s.bolge_no
AND i.`SERVIS_DURUMU` = 1
)
WHERE
1 = 1
GROUP BY
s.BOLGE

我得到了这个有线结果:

1428

它应该是 1。不是吗?

最佳答案

结果非常好,因为您只是为每一行计算 0 而不是 i.recno,因此两者的结果都是 1428。

要计算结果数,您可以像这样包装整个查询以获得 resultcount:

SELECT count(*) AS resultcount FROM (
SELECT
`s`.`FIRMA_UNVANI` AS `FIRMA_UNVANI`,
`s`.`RECNO` AS `RECNO`,
`s`.`BOLGE` AS `BOLGE`,
`s`.`BOLGE_NO` AS `BOLGE_NO`,
`s`.`DURUM` AS `DURUM`,
l.ILCE,
IL.SEHIR,
count(i.recno) AS NUMBER_OF_WORKS
FROM
`SERVISLER` `s`
LEFT JOIN KULLANICI k ON (s.BOLGE = k.KULLANICI)
LEFT JOIN kullanici_cihaz kc ON (k.RECNO = kc.KUL_RECNO)
LEFT JOIN servisler_ilceler c ON (s.RECNO = c.SER_RECNO)
INNER JOIN ILCE l ON (l.RECNO = c.ILCE_RECNO)
INNER JOIN IL ON (IL.ID = l.ILID)
LEFT JOIN ISEMRI i ON (
i.bolge = s.bolge_no
AND i.`SERVIS_DURUMU` = 1
)
GROUP BY
s.BOLGE
ORDER BY
IS_SAYISI
LIMIT 0, 15) AS temp

另请注意,WHERE 1=1 不是必需的。

关于mysql - 如何在 MySQL 中获取结果(行)数?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26313102/

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