android - AsyncTask 仍在阻塞 UI(UI 未响应)

Question

我有一个新闻应用程序，我可以在其中获取一些 XML 和 API 并立即插入到数据库中。我在获取/插入数据库过程中使用 AsyncTask。但是我仍然遇到障碍(UI 没有响应)

for (int i = 0; i < urls.size(); i++) {
    MyAsyncTask myAsyncTask =  new MyAsyncTask(urls.get(i));
    myAsyncTask.execute();
}

AsyncTask 类:

  private class MyAsyncTask extends AsyncTask<Void,Void,Void> {

    Url mUrl;
    public MyAsyncTask(Url url){
        this.mUrl = url;
    }


    @Override
    protected Void doInBackground(Void... params) {
        connect(mUrl.getUrl(),mUrl.getSourceName(),mUrl.getChoice(),mUrl.getId());
        return null;
    }

    @Override
    protected void onPostExecute(Void aVoid) {
        super.onPostExecute(aVoid);
        whenToInflate[mUrl.getId()] = true;
        mProgressState += 15;
        mProgress.setProgress(mProgressState);

        if (areAllTrue(whenToInflate)) {
            inflate(1907);
            Arrays.fill(whenToInflate, false);
        }
    }
}

连接方法:

private void connect(String url, final String sourceSite, final int sourceChoice, final int i) {


    stringRequest = new StringRequest(Request.Method.GET, url,
            new Response.Listener<String>() {
                @Override
                public void onResponse(String response) {
                    try {
                        if (sourceChoice == 14) {
                            database.insertFixtures(response, "FOOTBALL");
                        } else if (sourceChoice == 10 || sourceChoice == 20) {
                            database.insertNews(response, sourceChoice);
                        } else {
                            if (sourceChoice == 1) response = URLDecoder.decode(URLEncoder.encode(response, "iso8859-1"), "UTF-8");
                            database.insertNewsXML(response, sourceSite, sourceChoice);
                        }


                    } catch (IllegalStateException | IllegalArgumentException | UnsupportedEncodingException e) {
                        e.printStackTrace();
                    }

                }
            }, new Response.ErrorListener() {

        @Override
        public void onErrorResponse(VolleyError error) {
            error.printStackTrace();

        }
    });

    VolleySingleton.getInstance(getActivity()).addToRequestQueue(stringRequest);
}

VolleySingleton 类:

public class VolleySingleton {
    private static VolleySingleton instance;
    private static VolleySingleton ourInstance = new VolleySingleton();
    private RequestQueue requestQueue;

    private VolleySingleton() {
    }

    private VolleySingleton(Context context) {
        requestQueue = Volley.newRequestQueue(context);
    }

    public static VolleySingleton getInstance() {
        return ourInstance;
    }

    public static VolleySingleton getInstance(Context context) {
        if (instance == null) {
            instance = new VolleySingleton(context);
        }
        return instance;
    }

    public RequestQueue getRequestQueue() {
        return requestQueue;
    }


    public <T> void addToRequestQueue(Request<T> req) {
        req.setTag("App");
        getRequestQueue().add(req);
    }
}

Answer 1

那是因为你在更新Progress的进度。所以这就是它给出错误的原因。在 onProgressUpdate 方法 AsyncTask 中更新进度。