android - 我一直收到错误 "no value for url"

Question

这是我的java代码。我的 android studio 中的 url 没有任何值(value)。我打算从 wamp 服务器的 sql 数据库中获取图像。

public class MainActivity extends AppCompatActivity implements 
View.OnClickListener{
private String imagesJSON;

private static final String JSON_ARRAY ="result";
private static final String IMAGE_URL = "url";

private JSONArray arrayImages= null;

private int TRACK = 0;

private static final String IMAGES_URL = 
"http://192.168.43.214/apexStore2/image.php";

private Button buttonFetchImages;
private Button buttonMoveNext;
private Button buttonMovePrevious;
private ImageView imageView;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    imageView = (ImageView) findViewById(R.id.imageView);
    buttonFetchImages = (Button) findViewById(R.id.buttonFetchImages);
    buttonMoveNext = (Button) findViewById(R.id.buttonNext);
    buttonMovePrevious = (Button) findViewById(R.id.buttonPrev);
    buttonFetchImages.setOnClickListener(this);
    buttonMoveNext.setOnClickListener(this);
    buttonMovePrevious.setOnClickListener(this);
}


private void extractJSON(){
    try {

        JSONObject jsonObject = new JSONObject(imagesJSON);
        arrayImages = jsonObject.getJSONArray(JSON_ARRAY);
    } catch (JSONException e) {
        e.printStackTrace();
    }
}

private void showImage(){
    try {
        JSONObject jsonObject = arrayImages.getJSONObject(TRACK);
        getImage(jsonObject.getString(IMAGE_URL));
    } catch (JSONException e) {
        e.printStackTrace();
    }
}

private void moveNext(){
    if(TRACK < arrayImages.length()){
        TRACK++;
        showImage();
    }
}

private void movePrevious(){
    if(TRACK>0){
        TRACK--;
        showImage();
    }
}



private void getAllImages() {
    class GetAllImages extends AsyncTask<String,Void,String>{
        ProgressDialog loading;
        @Override
        protected void onPreExecute() {
            super.onPreExecute();
            loading = ProgressDialog.show(MainActivity.this, "Fetching 
Data...","Please Wait...",true,true);
        }

        @Override
        protected void onPostExecute(String s) {
            super.onPostExecute(s);
            loading.dismiss();
            imagesJSON = s;
            extractJSON();
            showImage();
        }

        @Override
        protected String doInBackground(String... params) {
            String uri = params[0];
            BufferedReader bufferedReader = null;
            try {
                URL url = new URL(uri);
                HttpURLConnection con = (HttpURLConnection) 
 url.openConnection();
                con.setRequestProperty("Content-Type", 
 "application/json;charset=utf-8");
                con.setRequestProperty("X-Requested-With", 
 "XMLHttpRequest");
                StringBuilder sb = new StringBuilder();

                bufferedReader = new BufferedReader(new 
 InputStreamReader(con.getInputStream()));

                String json;
                while((json = bufferedReader.readLine())!= null){
                    sb.append(json+"\n");
                }

                return sb.toString().trim();

            }catch(Exception e){
                return null;
            }
        }
    }
    GetAllImages gai = new GetAllImages();
    gai.execute(IMAGES_URL);
}

private void getImage(String urlToImage){
    class GetImage extends AsyncTask<String,Void,Bitmap>{
        ProgressDialog loading;
        @Override
        protected Bitmap doInBackground(String... params) {
            URL url = null;
            Bitmap image = null;

            String urlToImage = params[4];
            try {
                url = new URL(urlToImage);
                image = 
  BitmapFactory.decodeStream(url.openConnection().getInputStream());
            } catch (MalformedURLException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return image;
        }

        @Override
        protected void onPreExecute() {
            super.onPreExecute();
            loading = ProgressDialog.show(MainActivity.this,"Downloading 
  Image...","Please wait...",true,true);
        }

        @Override
        protected void onPostExecute(Bitmap bitmap) {
            super.onPostExecute(bitmap);
            loading.dismiss();
            imageView.setImageBitmap(bitmap);
        }
    }
    GetImage gi = new GetImage();
    gi.execute(urlToImage);
}

@Override
public void onClick(View v) {
    if(v == buttonFetchImages) {
        getAllImages();
    }
    if(v == buttonMoveNext){
        moveNext();
    }
    if(v== buttonMovePrevious){
        movePrevious();
    }
}

这是我的 PHP 代码。当我运行我的 php 代码时，我得到以下输出:

 {
"result": [{
    "product_img1": "product-131.jpg"
}, {
    "product_img1": "product-124.jpg"
}, {
    "product_img1": "product-118.jpg"
}, {
    "product_img1": "product-126.jpg"
}, {
    "product_img1": "USM_New_Logo1.jpg"
}, {
    "product_img1": "UI.PNG"
}, {
    "product_img1": "cat402.PNG"
}, {
    "product_img1": "launcher.png"
}]
}

我的 php 代码可以从 sql 数据库中获取图像，但是，我的 android studio 无法获取它。有什么解决办法吗？

<?php 
include ('classes/functions.php');

 $check_product = "SELECT * FROM products WHERE cat_id = '0';";
        $run_product_checking = mysqli_query($con, $check_product);
        $result = array();
    while($row = mysqli_fetch_array($run_product_checking)){
    array_push($result,
    array('product_img1'=>$row[4]

));
}

    echo json_encode(array("result"=>$result));
?>

Answer 1

将 IP 地址更改为其域名值。