android - 改造 2 : upload image to server and get strange response

Question

我使用 Retrofit 版本 2.0.1 将图像从我的 Android 手机上传到服务器，但出现了一个奇怪的错误。这是我发布到服务器的 API 接口(interface):

@POST("/vistek/myservice.php")
    Call<String> send(@Part("myFile") RequestBody file);

我的 Okttp 客户端是:

OkHttpClient.Builder httpClient = new OkHttpClient.Builder();
  HttpLoggingInterceptor interceptor2 = new HttpLoggingInterceptor();
  interceptor2.setLevel(HttpLoggingInterceptor.Level.HEADERS);

  HttpLoggingInterceptor interceptor = new HttpLoggingInterceptor();
  interceptor.setLevel(HttpLoggingInterceptor.Level.BODY);

  httpClient.addInterceptor(interceptor);
  httpClient.addInterceptor(interceptor2);

以及我将图像发送到服务器的功能:

public void sendImage(byte[] data)
    {
        MediaType MEDIA_TYPE_JPEG = MediaType.parse("image/jpeg");
        FileUploadService service = ServiceGenerator.createService(FileUploadService.class);

        RequestBody requestBody = RequestBody.create(MEDIA_TYPE_JPEG, data);

        Call<String> call = service.send(requestBody);

        call.enqueue(new Callback<String>() {
            @Override
            public void onResponse(Call<String> call, retrofit2.Response<String> response) {
                Log.d("Upload", "success = " + response.body());
            }

            @Override
            public void onFailure(Call<String> call, Throwable t) {

                Log.d("Upload","failure: " + t.getMessage());
            }
        });
    }

调用函数后，我得到了奇怪的响应，像这样:

������JFIF����������������C������C��������"�������� ������������������
04-12 17:30:11.144 11669-13785/mmlab.visualsearch D/OkHttp: ������������}��!1AQa"q2����#B��R��$3br.
04-12 17:30:11.144 11669-13785/mmlab.visualsearch D/OkHttp: %&'()*456789:CDEFGHIJSTUVWXYZcdefghijstuvwxyz ... ������������������
04-12 17:30:11.144 11669-13785/mmlab.visualsearch D/OkHttp: ��������w��!1AQaq"2�B���� #3R�br�

当我使用 Postman 测试 api 时，我的服务器正常工作:

POST /vistek/myservice.php HTTP/1.1
Host: demo.mmlab.uit.edu.vn
Cache-Control: no-cache
Postman-Token: ba965fb1-f7b9-7344-8b8a-ab46095668d1
Content-Type: multipart/form-data; boundary=----WebKitFormBoundary7MA4YWxkTrZu0gW

----WebKitFormBoundary7MA4YWxkTrZu0gW
Content-Disposition: form-data; name="myFile"; filename=""
Content-Type: 

----WebKitFormBoundary7MA4YWxkTrZu0gW

请帮助我了解我的代码发生了什么。提前致谢。

Answer 1

这不是不是奇怪的 react 。它是压缩的 (gzip)。

您似乎在请求的header 中添加了"accept-encoding", "gzip"。在这种情况下，您有责任解压缩响应。

所以你可以做的是:

只需从您的代码中省略 accept-encoding header 。 OkHttp 将添加自己的 accept-encoding header ，如果服务器以 gzip 响应，则 OkHttp 将默默地为您解压缩。

你也可以像这样手动解压:

StringBuilder stringBuilder = new StringBuilder();
ByteArrayInputStream bais = new ByteArrayInputStream(response.body().getBytes());
GZIPInputStream gzis = new GZIPInputStream(bais);
InputStreamReader reader = new InputStreamReader(gzis);
BufferedReader in = new BufferedReader(reader);

String readed;
while ((readed = in.readLine()) != null) {
    stringBuilder.append(readed);
}
in.close();
reader.close();
gzis.close();
String unZippedResponse = stringBuilder.toString();