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java - 保存到数据库使按钮无响应

转载 作者:行者123 更新时间:2023-11-29 01:21:11 24 4
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美好的一天。我想使用 pepraredStatement 插入到数据库中。但是,每当我添加数据库部分(连接和 pepraredStatement)时,“上传”按钮就会变得无响应。但是当我删除与数据库相关的任何内容时,我所有的按钮都可以使用。你可以在这里找到代码 http://pastebin.com/euKdWhr2 .

我将非常感谢任何帮助或建议。可能我在数据库部分遗漏了一些东西。

public void actionPerformed(ActionEvent ev)
{
String file = fileField.getText();
SetGetQuestionFileName pattern = new SetGetQuestionFileName(file);
ConnectToDatabase database = new ConnectToDatabase();
try
{

///////// check whether textfile is empty or not

if( ev.getActionCommand().equals("UPLOAD"))
{
if(fileField.getText().isEmpty())
{
JOptionPane.showMessageDialog(null,"File field can not be empty!!! Please try again.","ALERT", JOptionPane.ERROR_MESSAGE);
}
else
{
File fi = new File(fileField.getText());
//////////////// perform upload

try
{

String sql = "INSERT INTO testsystem.questionnaire (category_questions, questions, correct_answer)" + "VALUES (?, ?, ?)";

PreparedStatement st = null;

Connection dbconnection = database.getConnection();

st = dbconnection.prepareStatement(sql);

if(fi.getAbsoluteFile().exists())
{
List<String> lines = Files.readAllLines(Paths.get(fileField.getText()), Charset.defaultCharset());


for (int i = 0; i < lines.size(); i+=10)
{
String category = lines.get(i);
System.out.println(category);
String question = lines.get(i+1);
System.out.println(question);

String answers =
lines.get(i+2)+System.lineSeparator()
+lines.get(i+3)+System.lineSeparator()
+lines.get(i+4)+System.lineSeparator()
+lines.get(i+5);
System.out.println(answers);

String correct = lines.get(i+7);
System.out.println("correct answer is: "+correct);
System.out.println("----------------");


st.setString(1, category);
st.setString(2, answers);
st.setString(3, correct);
st.executeUpdate();

}

JOptionPane.showMessageDialog(null,"File has been successfully uploaded in the database.","NOTIFCATION",JOptionPane.INFORMATION_MESSAGE);
}
else

JOptionPane.showMessageDialog(null,"File could not be found. Please try again","ALERT",JOptionPane.ERROR_MESSAGE);
}

catch(SQLException ex)
{

}

catch(Exception ex)
{

}

最佳答案

actionPerformed() 方法由 ui 线程调用。如果您在此线程中执行长时间运行的任务,则 ui 将无响应,因为 ui 线程无法再执行 ui 工作,例如重新绘制 ui 或仅处理用户输入。

考虑使用 SwingWorker并阅读有关 concurrency in java 的教程.

编辑

i went to the proposed websites but i don't really understand what you meant by the SwingWorker . i'm not really used to the thread yet

这是一个工作示例,说明 SwingWorker 和长时间运行的后台任务如何工作。

public class SwingWorkerExample  {

public static class ProgressSimulatorSwingWoker extends SwingWorker<Void, Void> {

private BoundedRangeModel progressModel;

public ProgressSimulatorSwingWoker(BoundedRangeModel progressModel) {
this.progressModel = progressModel;
}

@Override
protected Void doInBackground() throws Exception {
int start = 0;
int end = 100;

progressModel.setMinimum(start);
progressModel.setMaximum(end);

for (int i = start; i <= end; i++) {
progressModel.setValue(i);
Thread.sleep(50);
}
return null;
}

}

public static void main(String[] args) {
JFrame jFrame = new JFrame("SwingWorker example");
jFrame.setSize(640, 150);
jFrame.setLocationRelativeTo(null); // center on screen
jFrame.setDefaultCloseOperation(WindowConstants.EXIT_ON_CLOSE);

Container contentPane = jFrame.getContentPane();
contentPane.setLayout(new BorderLayout());

JProgressBar jProgressBar = new JProgressBar();
final BoundedRangeModel model = jProgressBar.getModel();

JButton jButton = new JButton("Simulate Progress");
jButton.addActionListener(new ActionListener() {

@Override
public void actionPerformed(ActionEvent e) {
ProgressSimulatorSwingWoker progressSimulatorSwingWoker = new ProgressSimulatorSwingWoker(model);
progressSimulatorSwingWoker.execute();

}
});

contentPane.add(jProgressBar, BorderLayout.CENTER);
contentPane.add(jButton, BorderLayout.SOUTH);

jFrame.setVisible(true);
}
}

关于java - 保存到数据库使按钮无响应,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26925741/

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