行中的 SQL 求和被提取到列中？

Question

我有一个非常缓慢的搜索，它通过查找主要记录然后在一个线程中循环以对相关交易求和来完成。我试图让它在一个报表中工作，已经接近但仍然有交替借方和贷方的记录。

我无法弄清楚如何将借方行和贷方行向上拉到列中，以便每个日期和工作键有一行结果y。

SELECT j.dtmInvoicedOn, j.strJobKey, c.strCustName, strTransType, 
     SUM(r.dblTransactionAmount) AS SUM_dblTotalCharge 
     FROM tbljobs AS j
     INNER JOIN tblreceivledger AS r ON j.strJobKey = r.strJobKey 
     INNER JOIN tblcustomers AS c ON j.intCustomerID = c.intCustomerID 
     WHERE c.strCustomerName = 'Acme Runners Inc'
     GROUP BY j.strJobKey, c.strCustName, strTransType
     ORDER BY dtmInvoicedOn, strJobKey;

产生这样的输出，借方和贷方金额几乎交替出现

+----------------+---------------+------------------+--------------------+--------------------+
| dtmInvoicedOn  | strJobKey     | strCustomerName  | strTransactionType | SUM_dblTotalCharge |
+----------------+---------------+------------------+--------------------+--------------------+
| 2008-07-03     | 270876-1      | Acme Runners Inc | credit             |           -5531.52 | 
| 2008-07-11     | 270880-1      | Acme Runners Inc | debit              |            5058.54 | 
| 2008-07-11     | 270880-1      | Acme Runners Inc | credit             |           -5058.54 | 
| 2008-07-18     | 271468-1      | Acme Runners Inc | debit              |            5290.17 | 
| 2008-07-18     | 271468-1      | Acme Runners Inc | credit             |           -5290.17 | 
| 2008-11-07     | 286049-1      | Acme Runners Inc | debit              |            5230.44 | 
| 2008-11-14     | 286051-1      | Acme Runners Inc | debit              |            5375.14 | 
| 2008-11-21     | 286107-1      | Acme Runners Inc | debit              |            5572.33 | 
| 2008-11-28     | 286112-1      | Acme Runners Inc | debit              |            5123.42 | 

所以我希望它看起来像:

+----------------+---------------+------------------+----------+----------+
| dtmInvoicedOn  | strJobKey     | strCustomerName  |   credit |    debit |
+----------------+---------------+------------------+----------+----------+
| 2008-07-03     | 270876-1      | Acme Runners Inc | -5531.52 |        0 |
| 2008-07-11     | 270880-1      | Acme Runners Inc | -5058.54 |  5058.54 | 
| 2008-07-18     | 271468-1      | Acme Runners Inc | -5290.17 |  5290.17 | 
| 2008-11-07     | 286049-1      | Acme Runners Inc |        0 |  5230.44 | 
| 2008-11-14     | 286051-1      | Acme Runners Inc |        0 |  5375.14 | 
| 2008-11-21     | 286107-1      | Acme Runners Inc |        0 |  5572.33 | 
| 2008-11-28     | 286112-1      | Acme Runners Inc          0 |  5123.42 | 

请注意，服务器当前正在运行 mysql，但稍后将迁移到 postgres 和 sqlite。

谢谢

Answer 1

这应该可以完成工作:

SELECT j.dtmInvoicedOn, j.strJobKey, c.strCustName, strTransType, 
     SUM(CASE WHEN strTransType='credit' THEN r.dblTransactionAmount ELSE 0 END) AS SUM_CREDIT,
     SUM(CASE WHEN strTransType='debit' THEN r.dblTransactionAmount ELSE 0 END) AS SUM_DEBIT
FROM tbljobs AS j
     INNER JOIN tblreceivledger AS r ON j.strJobKey = r.strJobKey 
     INNER JOIN tblcustomers AS c ON j.intCustomerID = c.intCustomerID 
WHERE c.strCustomerName = 'Acme Runners Inc'
GROUP BY j.strJobKey, c.strCustName
ORDER BY dtmInvoicedOn, strJobKey;