ios - 如何在循环内增加索引并停止枚举？

Question

我遇到了需要循环的情况，但下面的代码仅返回最后一个索引值。我需要它返回下一个值并停止枚举。为了更好地解释，假设我有数字 0-10，当按下按钮时我需要索引增加 1。现在假设我一直按此按钮，直到索引达到 10，下次按时，索引需要返回到零(也称为循环。)

任何帮助将不胜感激，我绝对会接受最佳答案。

提前致谢!

//grabs current index in a scrollview
long long currentSelectedIndex = [preview.swipeView currentIndex];
long long totalNumberOfAvailableSlots = [preview.swipeView indexTotal]; //index total is never an absolute value

@autoreleasepool {
    //currentSelectedIndex is supposed/always to be zero on first run
    for (int i; = (int)currentSelectedIndex; i <= totalNumberOfAvailableSlots; i++){
        NSLog(@"loop: %d", i);
        if (i == totalNumberOfAvailableSlots){
            i = -1;
            [preview.swipeView scrollToIndex:i]; //this will cause [preview.swipeView currentIndex] to be updated with "i" value.
        }
    }
}

Answer 1

根据我的评论，您似乎想要的行为是自动滑动浏览 swipeView 的内容。

制作一个定时器调用swipeToNext方法:

myTimer = [NSTimer scheduledTimerWithTimeInterval: target:self selector:@selector(swipeToNext) userInfo:nil repeats:YES];

然后处理滑动:

- (void)swipeToNext {
if ([preview.swipeView currentIndex] < [preview.swipeView indexTotal]) {
//Can swipe forward
[preview.swipeView scrollToIndex:[preview.swipeView currentIndex]+1];
} else {
//At last index. Need to go to first.
[preview.swipeView scrollToIndex:0];
}
}