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ios - 类型 'AnyObject' 不符合协议(protocol) 'sequenceType'

转载 作者:行者123 更新时间:2023-11-29 01:05:02 25 4
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所以这是我的代码,我在以下行中收到错误,指出“类型'AnyObject'不符合协议(protocol)'sequenceType'”:

for bar in allBars {

我尝试了此处提出的解决方案( Type 'AnyObject' does not conform to protocol 'SequenceType' ),但它导致 Xcode 出现错误

我对 IOS 很陌生,所以这可能是一些愚蠢的东西

func loadBars(){
let path = NSBundle.mainBundle().pathForResource("donnes", ofType: "json")
let filename: String = "donnees.json"

do{
let data = try NSData(contentsOfFile: path!, options: NSDataReadingOptions.DataReadingMapped)
do{
let bars: AnyObject? = try NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions())
if let bars = bars as? Dictionary<String, AnyObject> {
print(bars)

let allBars = bars["bars"]

for bar in allBars {

let nouveauBar = Bar(id: bar["id"], name: bar["name"], adress: bar["adress"], url: bar["url"], image_url: bar["image_url"], tags: bar["tags"], longitude: bar["longitude"], latitude: bar["latitude"])

bars += nouveauBar
}

} else {
print("Level file '\(filename)' is not valid JSON")
}
}catch {
print("Level file '\(filename)' is not valid JSON: \(error)")
}


}catch {
print("Could not load level file: \(filename), error: \(error)")
}

}

这是 .json 文件的开头:

{
"code": 200,
"bars": [{
"id": 1627,
"address": "100 Rue Saint-Martin, 75004 Paris, France, Opera and Les Halles, Paris",
"name": "Caf\u00e9 Beaubourg",
"url": "/bar/paris/opera-and-les-halles/cafe-beaubourg",
"image_url": "https://prh-wbb-prod.s3.amazonaws.com/generic_640_480/WBB%20holding%20image3_54abcf7d218d1_55b8d2128eabb.jpg",
"tags": "Bar, Gay, Cafe, Dinner, Lunch",
"latitude": 48.860033826521,
"longitude": 2.3508920416641
}, {
"id": 1259,
"address": "19 Rue Beaubourg, 75004 Paris, France, Bastille and the Marais, Paris",
"name": "Georges",
"url": "/bar/paris/bastille-and-the-marais/georges",
"image_url": "https://prh-wbb-prod.s3.amazonaws.com/generic_640_480/WBB%20holding%20image4_54abcf6d1f68d_55b8d2015bb13.jpg",
"tags": "Serves Food, Great View, Rooftop, Terrace, Rock",
"latitude": 48.8603,
"longitude": 2.35097
}]

最佳答案

代替

if let bars = bars as? Dictionary<String, AnyObject> {

你可以写

if let bars = bars as? [String: AnyObject],
let allBars = bars["bars"] as? [[String: AnyObject]] {

这已经为您提供了 allBars大批。然后编译器知道每个 barallBars将具有类型 [String: AnyObject] ( Dictionary<String, AnyObject> 的缩写)允许您使用 bar作为字典。您仍然需要解开属性,例如 idname ,您可以按照与我上面的代码类似的方式进行操作。

关于ios - 类型 'AnyObject' 不符合协议(protocol) 'sequenceType',我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36516197/

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