android - Location.distanceTo 在近似距离计算中使用误差参数？

Question

我想知道 Location.distanceTo 方法是否会在近似位置时使用 Location 对象的精度字段，或者我是否必须自己将错误添加到这些字段。用法是将距离与接近值进行比较。

Float dist=currentLocation.distanceTo(loc2);

会不会是

if (dist<100meters)

或

if (dist+currentLocation.getAccuracy()+loc2.getAccuracy()<100meters)

Answer 1

看起来它忽略了准确性:
https://android.googlesource.com/platform/frameworks/base/+/donut-release/location/java/android/location/Location.java#400

 400     /**
 401      * Returns the approximate distance in meters between this
 402      * location and the given location.  Distance is defined using
 403      * the WGS84 ellipsoid.
 404      *
 405      * @param dest the destination location
 406      * @return the approximate distance in meters
 407      */
 408     public float distanceTo(Location dest) {
 409         // See if we already have the result
 410         synchronized (mResults) {
 411             if (mLatitude != mLat1 || mLongitude != mLon1 ||
 412                 dest.mLatitude != mLat2 || dest.mLongitude != mLon2) {
 413                 computeDistanceAndBearing(mLatitude, mLongitude,
 414                     dest.mLatitude, dest.mLongitude, mResults);
 415                 mLat1 = mLatitude;
 416                 mLon1 = mLongitude;
 417                 mLat2 = dest.mLatitude;
 418                 mLon2 = dest.mLongitude;
 419                 mDistance = mResults[0];
 420                 mInitialBearing = mResults[1];
 421             }
 422             return mDistance;
 423         }
 424     }