php mysql批量记录更新？

Question

我正在尝试使用以下代码更新多个 mysql 记录:

<strong>Update multiple rows in mysql</strong><br> 

<?php
$host="localhost"; // Host name 
$username=""; // Mysql username 
$password=""; // Mysql password 
$db_name="test"; // Database name 
$tbl_name="test_mysql"; // Table name 

// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB");

$sql="SELECT * FROM $tbl_name";
$result=mysql_query($sql);

// Count table rows 
$count=mysql_num_rows($result);
?>
<table width="500" border="0" cellspacing="1" cellpadding="0">
<form name="form1" method="post" action="">
<tr> 
<td>
<table width="500" border="0" cellspacing="1" cellpadding="0">


<tr>
<td align="center"><strong>Id</strong></td>
<td align="center"><strong>Name</strong></td>
<td align="center"><strong>Lastname</strong></td>
<td align="center"><strong>Email</strong></td>
</tr>
<?php
while($rows=mysql_fetch_array($result)){
?>
<tr>
<td align="center"><? $id[]=$rows['id']; ?><? echo $rows['id']; ?></td>
<td align="center"><input name="name[]" type="text" id="name" value="<? echo $rows['name']; ?>"></td>
<td align="center"><input name="lastname[]" type="text" id="lastname" value="<? echo $rows['lastname']; ?>"></td>
<td align="center"><input name="email[]" type="text" id="email" value="<? echo $rows['email']; ?>"></td>
</tr>
<?php
}
?>
<tr>
<td colspan="4" align="center"><input type="submit" name="Submit" value="Submit"></td>
</tr>
</table>
</td>
</tr>
</form>
</table>
<?php
// Check if button name "Submit" is active, do this 
if($Submit){
   for($i=0;$i<$count;$i++){
     $sql1="UPDATE $tbl_name 
            SET name='$name[$i]', 
                lastname='$lastname[$i]', 
                email='$email[$i]' 
                WHERE id='$id[$i]'";
     $result1=mysql_query($sql1);
   }
}

if($result1){
header("location:update_multiple.php");
?>

它在输入文本框中显示来自数据库的记录，但是当我用新记录更改旧记录然后提交时，没有任何反应，页面刷新为旧值。

Answer 1

您需要使用 $_POST['Submit'] 检查表单是否已提交。您还可以使用隐藏的输入字段来跟踪要更新的每一行:

<input type="hidden" name="id[]" value="<?php echo $row['id']; ?>" />

然后在处理你的提交时你应该做这样的事情:

if(isset($_POST['Submit'])) {
   $ids = $_POST['id'];
   $names = $_POST['name'];
   $lastnames = $_POST['lastname'];
   $emails = $_POST['email'];
   //
   foreach($ids as $id) {
      // update the record based on the id and supplied data
   }
}

当然，更新过程应该在您从数据库中检索行之前执行。换句话说，上面的代码应该放在脚本的顶部附近。至少在:

$sql="SELECT * FROM $tbl_name";
$result=mysql_query($sql);