php - 单击保存按钮时如何保存在多个表中？

Question

我需要同时将动态文本框中的值保存在不同的表格中。有人可以帮我做这个吗？我有 4 个表需要填写。这是我的表格及其字段:

表 1- desk_id- 办公 table 用户- desk_report- desk_action

表 2- print_id- 打印品牌- 打印模型- 打印报告- print_action

表 3- 电话号码- 本地电话- 电话用户- 电话报告- tel_action

表 4- remarks_id- 备注

我的 PHP 代码:

   <?php

$con = mysql_connect ("localhost","root","nasi") or die
('cannot connect to database error: '.mysql_error());


if (isset($_POST['desk_user']) &&
isset($_POST['desk_report']) &&
isset($_POST['desk_action']) &&
isset($_POST['print_brand']) &&
isset($_POST['print_model']) &&
isset($_POST['print_report']) &&
isset($_POST['print_action']) &&
isset($_POST['tel_local']) &&
isset($_POST['tel_user']) &&
isset($_POST['tel_report']) &&
isset($_POST['tel_action']) &&
isset($_POST['remarks']))
{

$desk_user = $_POST['desk_user'];
$desk_report = $_POST['desk_report'];
$desk_action = $_POST['desk_action'];
$print_brand = $_POST['print_brand'];
$print_model = $_POST['print_model'];
$print_report = $_POST['print_report'];
$print_action = $_POST['print_action'];
$tel_local = $_POST['tel_local'];
$tel_user = $_POST['tel_user'];
$tel_report = $_POST['tel_report'];
$tel_action = $_POST['tel_action'];
$remarks = $_POST['remarks'];

if (!empty($desk_user)&& !empty($desk_report)&& !empty($desk_action) && !empty($print_brand) && !empty($print_model) && !empty($print_report) && !empty($print_action) && !empty($tel_local) && !empty($tel_user) && !empty($tel_report) && !empty($tel_action) && !empty($remarks)) {

mysql_select_db("csr", $con);
 $queries = array(); 
for($i=0; $i<count($desk_user || $print_brand || $tel_local || $remarks); $i++) 
{ 
    $queries [] = "('" .$desk_user [$i ] . "', '" .$desk_report [$i ] . "', '" .$desk_action [$i ] . "')" ;

    $queries1 [] = "( '" .$print_brand [$i ] . "', '" .$print_model [$i ] . "', '" .$print_report [$i ] . "', '" .$print_action [$i ] . "')" ;

    $queries2 [] = "('" .$tel_local [$i ] . "', '" .$tel_user [$i ] . "', '" .$tel_report [$i ] . "', '" .$tel_action [$i ] . "')" ;

    $queries3 [] = "('" .$remarks [$i ] . "')" ;
} 

if(count($queries) == 0) 
{ 
    # Nothing passed 
    # exit 
} 

$query = "insert into desktoplaptop (desk_user, desk_report, desk_action tel_local) values " . implode(", ", $queries) ; 

$query1 = "insert into printer (print_brand, print_model, print_report, print_action) values " . implode(", ", $queries1) ; 

$query2 = "insert into tel (tel_user, tel_report, tel_action) values " . implode(", ", $queries2) ;  

$query3 = "insert into remarks (remarks) values " . implode(", ", $queries3) ;  

if ($sql_run = mysql_query($query) || $sql_run = mysql_query($query1) || $sql_run = mysql_query($query2) || $sql_run = mysql_query($query3)) {
                            echo 'ok.'; 
                                }
                        else {
                                    echo '*Sorry, we couldn\'t register you at this time. Try again later.';

                                    }

}

}

?>

Answer 1

如果有四个表，则每个表都需要一个唯一的 INSERT 语句。使用您提供的代码，您只需命名一个表:desktoplaptop

如果上面的列表所建议的实际上有四个唯一的表，您将需要编写一个唯一的 INSERT 语句来引用每个表的架构。

例如:

$queries = array();
if(!empty($desk_user)) {
    $queries[] = "INSERT into desktop (desk_user, desk_report, desk_action) VALUES ('" . $desk_user . "', '" .$desk_report . "', '" . $desk_action . "')'";
}

对其他 3 个表重复

foreach($queries as $query) {
    if ($sql_run = mysql_query($query)) {
       echo 'ok.'; 
    } else {
       echo '*Sorry, we couldn\'t register you at this time. Try again later.';
    }
}

请注意，如果您从网络表单中获取输入，您还需要 mysql_escape_string()每个 $_POST 变量以防止注入(inject)。此外，您似乎错误地使用了 count() 函数——当它需要一个数组时，您向它传递了一个 bool 表达式。总的来说，我建议再看看您的代码究竟是如何运行的。