gpt4 book ai didi

android - 如何从sd卡上传图片到服务器文件夹

转载 作者:行者123 更新时间:2023-11-29 00:34:19 28 4
gpt4 key购买 nike

我想从我的 sd 卡上传图像到服务器的文件夹中。我有以下信息 http://mywebsite.myworks.com/parent/webservices/myuploader.ashx (发布)

Content-Disposition: form-data; name="Filename"
FilName.jpg

Content-Disposition: form-data; name="password"
mypassword

Content-Disposition: form-data; name="action"
upload

Content-Disposition: form-data; name="parentNodeId"
1297

Content-Disposition: form-data; name="replaceExisting"
0

Content-Disposition: form-data; name="username"
admin

Content-Disposition: form-data; name="Filedata"; filename="2012-11-07 11-03-37.jpg"
Content-Type: application/octet-stream
[DATA]

基本上我想要的是将图像上传到文件夹。到目前为止我所了解的是上传到 parentNodeId 为 1297 的文件夹。我看到了一些关于如何将图像上传到 php 服务器的教程。基于我写的一个功能。我在下面分享它

private void doFileUpload() {
HttpURLConnection conn = null;
DataOutputStream dos = null;
DataInputStream inStream = null;
String exsistingFileName = "/sdcard/r.jpg";

// Is this the place are you doing something wrong.
String lineEnd = "rn";
String twoHyphens = "--";
String boundary = "*****";

int bytesRead, bytesAvailable, bufferSize;
byte[] buffer;
int maxBufferSize = 1 * 1024 * 1024;
String responseFromServer = "";
String urlString = "http://mywebsite.myworks.com/parent/webservices/myuploader.ashx";

try {
// ------------------ CLIENT REQUEST
Log.e("UploadMe", "Inside second Method");
FileInputStream fileInputStream = new FileInputStream(new File(exsistingFileName));

// open a URL connection to the Servlet
URL url = new URL(urlString);

// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();

// Allow Inputs
conn.setDoInput(true);

// Allow Outputs
conn.setDoOutput(true);

// Don't use a cached copy.
conn.setUseCaches(false);

// Use a post method.
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
// conn.setRequestProperty("Content-Type",
// "multipart/form-data;boundary="+boundary);
conn.setRequestProperty("Content-Type", "application/octet-stream");

dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"Filename\";filename=\""
+ exsistingFileName + "\"" + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"Filename\";filename=\""
+ "r.jpg" + "\"" + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"password\";filename=\""
+ "mypassword" + "\"" + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"action\";filename=\""
+ "upload" + "\"" + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"parentNodeId\";filename=\""
+ "-1" + "\"" + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"replaceExisting\";filename=\""
+ "0" + "\"" + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"username\";filename=\""
+ "admin" + "\"" + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"Filedata\";filename=\""
+ "2012-11-07 11-03-37.jpg" + "\"" + lineEnd);

dos.writeBytes(twoHyphens + boundary + lineEnd);

dos.writeBytes(lineEnd);
Log.e("UploadMe", "Headers are written");

// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];

// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);

while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
}

// send multipart form data necesssary after file data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

// close streams
Log.e("UploadMe", "File is written");
fileInputStream.close();
dos.flush();
dos.close();

}

catch (MalformedURLException ex)

{

Log.e("UploadMe", "error: " + ex.getMessage(), ex);

}

catch (IOException ioe)

{

Log.e("UploadMe", "error: " + ioe.getMessage(), ioe);

}

// ------------------ read the SERVER RESPONSE
try {
inStream = new DataInputStream(conn.getInputStream());
String str;

while ((str = inStream.readLine()) != null) {
Log.e("UploadMe", "Server Response" + str);
}

inStream.close();
}

catch (IOException ioex) {
Log.e("UploadMe", "error: " + ioex.getMessage(), ioex);
}

}

程序运行时没有任何崩溃,我从我的日志猫输出中得到这些。但是我在我的服务器文件夹中看不到任何东西。

11-22 10:26:39.546: E/UploadMe(3363): Inside second Method
11-22 10:26:39.843: E/UploadMe(3363): Headers are written
11-22 10:26:39.851: E/UploadMe(3363): File is written
11-22 10:26:40.820: E/UploadMe(3363): Server Response<?xml version="1.0"?>
11-22 10:26:40.820: E/UploadMe(3363): Server Response<MediaResponse xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" success="false" />

由于我不知道上传文件到服务器,这是上传文件的方式吗?

最佳答案

一个可用的库调用 android-async-http-1.4.2.jar 使用它你还可以上传带有 post 字符串数据的文件

这是示例代码

RequestParams params = new RequestParams();
params.put("fname", "name");// here write your parameter name and its value
params.put("file", new File(filePath)); // Upload a File
// params.put("profile_picture2", someInputStream); // Upload an
// InputStream
// params.put("profile_picture3", new ByteArrayInputStream(someBytes));
// // Upload some bytes

AsyncHttpClient client = new AsyncHttpClient();
client.post(urlServer, params, new AsyncHttpResponseHandler() {
@Override
public void onSuccess(String arg0) {
super.onSuccess(arg0);
Log.v("from response", arg0);
}
});

这里是jar下载链接

https://github.com/loopj/android-async-http/downloads

关于android - 如何从sd卡上传图片到服务器文件夹,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13506167/

28 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com