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android - 游标返回错误值 - sqlite - Android

转载 作者:行者123 更新时间:2023-11-29 00:33:40 29 4
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我正在开发一个短信应用程序,我正在尝试从每次对话中获取最后的短信。

这是我的 SQL 语句:

SELECT MAX(smsTIMESTAMP) AS smsTIMESTAMP,_id, smsID, smsCONID, smsMSG, smsNUM, smsREAD, smsTYPE, smsSHORTMSG, COUNT(*) AS smsNUMMESSAGES FROM sms GROUP BY smsCONID ORDER BY smsTIMESTAMP desc

我在 SQLite Expert 中运行查询并得到正确的响应:

enter image description here

然而,当我在我的应用程序中运行它时,我得到:

enter image description here

这是我的 table

enter image description here

这是我的数据操纵器类:

public class DataManipulator {
private static final String DATABASE_NAME = "smsapplication.db";
private static final int DATABASE_VERSION = 3;
static final String TABLE_NAME = "sms";
private static Context context;
static SQLiteDatabase db;
private static DataManipulator instance;

private SQLiteStatement insertStmt;

private static final String INSERT = "insert or ignore into "
+ TABLE_NAME + " (smsID, smsCONID, smsMSG, smsNUM, smsREAD, smsTIMESTAMP, smsTYPE, smsSHORTMSG) values (?,?,?,?,?,?,?,?)";

public DataManipulator(Context context) {
DataManipulator.context = context;
OpenHelper openHelper = new OpenHelper(DataManipulator.context);
DataManipulator.db = openHelper.getWritableDatabase();
this.insertStmt = DataManipulator.db.compileStatement(INSERT);
}
public static DataManipulator getInstance(Context mContext)
{
if(instance == null)
{
instance = new DataManipulator(mContext);
}
return instance;
}
public long insert(int smsID, int smsCONID, String smsMSG,
String smsNUM, int smsREAD, long smsTIMESTAMP, String smsTYPE, String smsSHORTMSG) {
this.insertStmt.bindLong(1, smsID);
this.insertStmt.bindLong(2, smsCONID);
this.insertStmt.bindString(3, smsMSG);
this.insertStmt.bindString(4, smsNUM);
this.insertStmt.bindLong(5, smsREAD);
this.insertStmt.bindString(6, String.valueOf(smsTIMESTAMP));
this.insertStmt.bindString(7, smsTYPE);
this.insertStmt.bindString(8, smsSHORTMSG);
return this.insertStmt.executeInsert();
}

public void deleteAll() {
db.delete(TABLE_NAME, null, null);
}

public Cursor getLastSmsForAllConversations()
{
Cursor cursor = db.query(TABLE_NAME, new String[] {"_id"," MAX(smsTIMESTAMP) AS smsTIMESTAMP ", "smsCONID", "smsNUM", "smsREAD", "smsTYPE","smsSHORTMSG","COUNT(*) AS smsNUMMESSAGES" },
null, null, "smsCONID", null, "smsTIMESTAMP desc");
return cursor;
}
public Cursor getConversationMessages(int conID)
{
Cursor cursor = db.query(TABLE_NAME, new String[] {"_id", "smsID", "smsCONID", "smsMSG", "smsNUM", "smsREAD", "smsTIMESTAMP", "smsTYPE","smsSHORTMSG" },
"smsCONID="+conID, null, null, null, "smsTIMESTAMP asc");
return cursor;
}
public void printCursor()
{
Cursor cursor = db.rawQuery("SELECT MAX(smsTIMESTAMP) AS smsTIMESTAMP,_id, smsID, smsCONID, smsMSG, smsNUM, smsREAD, smsTYPE, smsSHORTMSG, COUNT(*) AS smsNUMMESSAGES FROM sms GROUP BY smsCONID ORDER BY smsTIMESTAMP desc", null);

// db.query(TABLE_NAME, new String[] {"_id","smsTIMESTAMP AS smsTIMESTAMP ", "smsCONID", "smsNUM", "smsREAD", "smsTYPE","smsSHORTMSG" },"smsCONID=40", null, null, null, "smsTIMESTAMP desc");
if (cursor.moveToFirst()){
do{
String data ="";
data= cursor.getString(cursor.getColumnIndex("smsTIMESTAMP"))+" - " +cursor.getString(cursor.getColumnIndex("smsSHORTMSG"));
Log.i("data", data);
}while(cursor.moveToNext());
}
cursor.close();
}

private static class OpenHelper extends SQLiteOpenHelper {

OpenHelper(Context context) {
super(context, DATABASE_NAME, null, DATABASE_VERSION);
}

@Override
public void onCreate(SQLiteDatabase db) {
db.execSQL("CREATE TABLE " + TABLE_NAME + " (_id INTEGER , smsID INTEGER PRIMARY KEY, smsCONID INTEGER, smsMSG TEXT,smsNUM TEXT, smsREAD INTEGER, smsTIMESTAMP INTEGER, smsTYPE TEXT, smsSHORTMSG TEXT)");
}

@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
db.execSQL("DROP TABLE IF EXISTS " + TABLE_NAME);
onCreate(db);
}
@Override
public synchronized void close() {

if (db != null)
db.close();

super.close();

}
}
}

最佳答案

当您使用 GROUP BY 时,结果的每一行对应于原始表的多行。这些结果的计算方式有以下三种可能性:

  • 具有聚合函数(如 MAXCOUNT)的列计算组中所有行的值;
  • 出现在 GROUP BY 子句中的列只是取自组中的任何记录(因为组中的所有记录对该列具有相同的值);
  • 其他列是个问题,因为组中的行可能有不同的值。在标准 SQL 中,这样的列是被禁止的; SQLite 允许它们,但只是为您提供组中任意随机行的值,这几乎不是您想要的。从 SQLite 3.7.11 开始,您可以从匹配 MINMAX 的行中获取值;这是您在 SQLite Exprert 中看到的,但在装有较旧 SQLite 的 Android 上却看不到。

要解决您的问题,您必须首先使用 GROUP BY 获取足够的信息来识别您想要的记录:

SELECT smsCONID,                            -- OK: used in GROUP BY
MAX(smsTIMESTAMP) AS smsTIMESTAMP, -- OK: aggregate MAX
COUNT(*) AS smsNUMMESSAGES -- OK: aggregate COUNT
FROM sms
GROUP BY smsCONID
ORDER BY smsTIMESTAMP DESC

然后,将该结果表与原始 sms 表连接起来,以获取这些记录的其他列:

SELECT *
FROM (SELECT smsCONID,
MAX(smsTIMESTAMP) AS smsTIMESTAMP,
COUNT(*) AS smsNUMMESSAGES
FROM sms
GROUP BY smsCONID) AS grouped
JOIN sms
ON grouped.smsCONID = sms.smsCONID
AND grouped.smsTIMESTAMP = sms.smsTIMESTAMP
ORDER BY smsTIMESTAMP DESC

关于android - 游标返回错误值 - sqlite - Android,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/13916210/

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