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python - Django mysql 表名未验证

转载 作者:行者123 更新时间:2023-11-29 00:31:04 26 4
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我将类添加到 Django 应用程序模型以创建 mysql 表。我在“歌曲”表中有“下载”表和“下载”列。

当我想同步数据库时,Django 返回错误:

CommandError: One or more models did not validate:
mp3mid.downloads: Reverse query name for field 'song' clashes with field 'songs.downloads'. Add a related_name argument to the definition for 'song'.

为什么表和列不能重名?

这是我的模型.py:

from django_evolution.mutations import *
from django.db import models

class singers(models.Model):
name = models.CharField(max_length = 255)
category = models.ForeignKey(categories)

class songs(models.Model):
name = models.CharField(max_length = 255)
singer = models.ForeignKey(singers)
downloads = models.IntegerField(max_length = 11)
exclusive = models.BooleanField(default = 0)
hit = models.BooleanField(default = 0)
date = models.DateTimeField(auto_now_add = True)
link = models.CharField(max_length = 255)

class downloads(models.Model):
song = models.ForeignKey(songs)
date = models.DateTimeField(auto_now_add = True)

最佳答案

Django 允许您 make queries that span relationships .

在您的情况下,从 downloadssongs 的外键意味着您通常可以按照从歌曲到下载的关系向后查询:

from datetime import datetime
# fetch all songs with a download with a date on or after 2013-05-01.
songs = song.objects.filter(downloads__date__gte=datetime(2013,5,1))

但是,在这种情况下您不能这样做,因为 downloads 与您的 songs.downloads 字段冲突。

您有几个选择。首先,您可以设置 related_name为您的外键,如您的错误消息所建议的那样。

class downloads(models.Model):
song = models.ForeignKey(songs, related_name="related_downloads")

或者,您可以重命名您的 song.downloads 字段。

class songs(models.Model):
...
num_downloads = models.IntegerField(max_length = 11)

顺便说一句,我建议您将模型重命名为 SingerSongDownload(大写,单数而不是复数),以便遵循 Django 约定。

关于python - Django mysql 表名未验证,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/16499380/

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