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mysql - 带有 Wordpress 帖子和 post_meta 的子查询

转载 作者:行者123 更新时间:2023-11-29 00:28:11 25 4
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我知道这是不对的,尽管这是可行的。

我需要找到给定半径和位置附近的所有帖子(作为收入),但我需要子查询 post_meta 中的经纬度信息。

它会伤害你的眼睛,所以在这里:

/*
lat -23.6480147
lng -46.704116399999975
radius 20km
6371 para km e 3959 para miles
*/
SELECT vision_outlet.wp_posts.ID as 'ID',
vision_outlet.wp_posts.post_title as 'Nome',
(
SELECT vision_outlet.wp_postmeta.meta_value
FROM vision_outlet.wp_postmeta
WHERE vision_outlet.wp_postmeta.meta_key = 'formatted_address'
AND vision_outlet.wp_postmeta.post_id = vision_outlet.wp_posts.ID
) as 'formatted_address' ,
(
SELECT vision_outlet.wp_postmeta.meta_value
FROM vision_outlet.wp_postmeta
WHERE vision_outlet.wp_postmeta.meta_key = 'lat'
AND vision_outlet.wp_postmeta.post_id = vision_outlet.wp_posts.ID
) as 'lat',
(
SELECT vision_outlet.wp_postmeta.meta_value
FROM vision_outlet.wp_postmeta
WHERE vision_outlet.wp_postmeta.meta_key = 'lng'
AND vision_outlet.wp_postmeta.post_id = vision_outlet.wp_posts.ID
) as 'lng',
(
6371 * acos( cos( radians(-23.6480147) ) * cos( radians
(
(
SELECT vision_outlet.wp_postmeta.meta_value
FROM vision_outlet.wp_postmeta
WHERE vision_outlet.wp_postmeta.meta_key = 'lat'
AND vision_outlet.wp_postmeta.post_id = vision_outlet.wp_posts.ID
)
) ) * cos( radians
(
(
SELECT vision_outlet.wp_postmeta.meta_value
FROM vision_outlet.wp_postmeta
WHERE vision_outlet.wp_postmeta.meta_key = 'lng'
AND vision_outlet.wp_postmeta.post_id = vision_outlet.wp_posts.ID
)
) - radians(-46.704116399999975) ) + sin( radians(-23.6480147) ) * sin( radians
(
(
SELECT vision_outlet.wp_postmeta.meta_value
FROM vision_outlet.wp_postmeta
WHERE vision_outlet.wp_postmeta.meta_key = 'lat'
AND vision_outlet.wp_postmeta.post_id = vision_outlet.wp_posts.ID
)
) ) )
) as 'distance'

FROM vision_outlet.wp_posts, vision_outlet.wp_postmeta

WHERE vision_outlet.wp_posts.ID = vision_outlet.wp_postmeta.post_id
AND vision_outlet.wp_posts.post_status = 'publish'
AND vision_outlet.wp_postmeta.meta_key = 'formatted_address'
HAVING distance < 20
ORDER BY distance

问题是:我是否需要考虑创建一个新表,或者有什么方法可以重构它吗?

最佳答案

现在好多了

/*
lat -23.6480147
lng -46.704116399999975
radius 20km
6371 para km e 3959 para miles
*/
SELECT wp_posts.ID,
wp_posts.post_title,
pm1.meta_value as formatted_address,
pm2.meta_value as lat,
pm3.meta_value as lng,
6371 * acos( cos( radians(-23.6480147) ) * cos( radians( pm2.meta_value ) ) * cos( radians ( pm3.meta_value ) - radians(-46.704116399999975) ) + sin( radians(-23.6480147) ) * sin( radians ( pm2.meta_value ) ) ) as 'distance'

FROM wp_posts
LEFT JOIN wp_postmeta AS pm1 ON (wp_posts.ID = pm1.post_id AND pm1.meta_key='formatted_address')
LEFT JOIN wp_postmeta AS pm2 ON (wp_posts.ID = pm2.post_id AND pm2.meta_key='lat')
LEFT JOIN wp_postmeta AS pm3 ON (wp_posts.ID = pm3.post_id AND pm3.meta_key='lng')

WHERE wp_posts.post_type = 'outlet'
AND wp_posts.post_status = 'publish'
HAVING distance < 20
ORDER BY distance

关于mysql - 带有 Wordpress 帖子和 post_meta 的子查询,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17975033/

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