gpt4 book ai didi

MySQL 将数据库列从 Blob 转换为单独的部分

转载 作者:行者123 更新时间:2023-11-29 00:26:19 24 4
gpt4 key购买 nike

我试图从一个旧的 MySQL 表中取出一个 blob 并为它创建一个新表,以努力达到第一范式。然而,事实证明,要将数据库中已有的数据从 blob 转换为新表中的多行并非易事。

用SQL命令实现转换最简单的方法是什么?

父表:

CREATE  TABLE TEST.People (
`id` INT AUTO_INCREMENT,
`age` INT,
`height` INT,
`weight` INT ,
`variations` BLOB DEFAULT NULL,
PRIMARY KEY (`id`),
);

新表:

CREATE  TABLE TEST.Variations (
`id` INT AUTO_INCREMENT,
`chr` INT,
`start` INT,
`stop` INT ,
`type` ENUM('SNP','INDEL','CNV') DEFAULT NULL,
PRIMARY KEY (`id`),
);

当我运行 SELECT id,variations FROM TEST.People;我得到:

+----+----------------------------------------------------------------------------------------------------------------------+
| id | variations |
+----+----------------------------------------------------------------------------------------------------------------------+
| 3 | xp t !3:124093754-124467278/CNVt 7:78030601-79638023/CNV |
| 6 | xp |
| 9 | xp |
| 12 | xp t !1:84289718-85466763/CNV |
| 15 | xp |
| 18 | xp |
| 21 | xp |
| 24 | xp |
| 27 | xp |
| 30 | xp t !10:166909544-166909544/SNPt !2:66903445-66903445/SNPt !2:166897864-166897864/CNVt !7:6892788-6892788/SNP |
+----+----------------------------------------------------------------------------------------------------------------------+

所以我希望 TEST.Variations 表在转换后具有的是:

+----+-----+-----------+-----------+----------+
| id | chr | start | stop | type |
+----+-----+-----------+-----------+----------+
| 3 | 3 | 124093754 | 124467278 | CNV |
| 3 | 7 | 78030601 | 79638023 | CNV |
| 12 | 1 | 84289718 | 85466763 | CNV |
| 30 | 10 | 166909544 | 166909544 | SNP |
| 30 | 2 | 66903445 | 66903445 | SNP |
| 30 | 2 | 166897864 | 166897864 | CNV |
| 30 | 7 | 6892788 | 6892788 | SNP |
+----+-----+-----------+-----------+----------+

最佳答案

首先两件事:

  1. 您的 id 3 的数据不一致。7:... 之前没有 !。我希望这只是一个错字

    xp   t !3:124093754-124467278/CNVt 7:78030601-79638023/CNV
    ^^
  2. 如果你想在你的目标表中有一个auto_increment列,那么你的架构应该看起来像这样

    CREATE  TABLE variations 
    (
    `var_id` INT NOT NULL AUTO_INCREMENT,
    `id` INT, -- id from People goes here and it's not UNIQUE
    `chr` INT,
    `start` INT,
    `stop` INT ,
    `type` ENUM('SNP','INDEL','CNV') DEFAULT NULL,
    PRIMARY KEY (`var_id`)
    );

现在您可以通过查询将数据从People 传输到Variations

INSERT INTO variations (id, chr, start, stop, type)
SELECT id,
SUBSTRING_INDEX(variation, ':', 1) chr,
SUBSTRING_INDEX(SUBSTRING_INDEX(variation, '-', 1), ':', -1) start,
SUBSTRING_INDEX(SUBSTRING_INDEX(variation, '-', -1), '/', 1) stop,
SUBSTRING_INDEX(variation, '/', -1) type
FROM
(
SELECT p.id, SUBSTRING_INDEX(SUBSTRING_INDEX(p.variations, 't !', n.n), 't !', -1) variation
FROM
(
SELECT id, SUBSTR(variations, 9) variations
FROM people
WHERE variations LIKE 'xp t !%'
) p CROSS JOIN
(
SELECT a.N + b.N * 10 + 1 n
FROM
(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) a
,(SELECT 0 AS N UNION ALL SELECT 1 UNION ALL SELECT 2 UNION ALL SELECT 3 UNION ALL SELECT 4 UNION ALL SELECT 5 UNION ALL SELECT 6 UNION ALL SELECT 7 UNION ALL SELECT 8 UNION ALL SELECT 9) b
ORDER BY n
) n
WHERE n.n <= 1 + (LENGTH(p.variations) - LENGTH(REPLACE(p.variations, 't !', ''))) / 3
ORDER BY id
) q
ORDER BY id, chr, start, stop, type;

注意:此查询将拆分每个 ID 最多 100 个变体。如果您需要更多或更少,您可以通过使用 n 别名编辑内部子查询来调整限制,这会即时生成数字(计数)表。

结果:

| VAR_ID | ID | CHR |     START |      STOP | TYPE ||--------|----|-----|-----------|-----------|------||      1 |  3 |   3 | 124093754 | 124467278 |  CNV ||      2 |  3 |   7 |  78030601 |  79638023 |  CNV ||      3 | 12 |   1 |  84289718 |  85466763 |  CNV ||      4 | 30 |  10 | 166909544 | 166909544 |  SNP ||      5 | 30 |   2 | 166897864 | 166897864 |  CNV ||      6 | 30 |   2 |  66903445 |  66903445 |  SNP ||      7 | 30 |   7 |   6892788 |   6892788 |  SNP |

这是 SQLFiddle 演示

关于MySQL 将数据库列从 Blob 转换为单独的部分,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18749635/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com