android - 通过 SOAP 发送 xml 数据时无法获得响应

Question

我正在尝试通过 SOAP 发送 xml 以获得特定响应。我正在尝试使用默认密码登录。正确的响应将包含一个用户 ID，但我得到的是零。

StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder()
            .permitAll().build();
    StrictMode.setThreadPolicy(policy);

    // Create the soap request object
    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

    // Set the property info for the to currency
    PropertyInfo value = new PropertyInfo();
    value.setName("xml");
    value.setValue(xml);
    value.setType(String.class);
    request.addProperty(value);


    // Create the envelop.Envelop will be used to send the request
    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
            SoapEnvelope.VER11);
    envelope.setOutputSoapObject(request);        
    envelope.dotNet = true;       

    HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);

    try {
        androidHttpTransport.call(SOAP_ACTION, envelope);            
        SoapObject response = (SoapObject)envelope.bodyIn;

        result = response.getProperty(0).toString();           

        Log.i("RES", result);


    } catch (Exception e) {

        result = "EXCEP " + e.toString();
    }

我的xml是

     <?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"        xmlns:xsd="http://www.w3.org/2001/XMLSchema"    xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
<soap:Body>
<pinLogin xmlns="http://tempuri.org/">
  <pin1>string</pin1>
  <pin2>string</pin2>
  <pin3>string</pin3>
  <pin4>string</pin4>
</pinLogin>

我应该得到这样的回应

<soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
 <soap:Body>
 <pinLoginResponse xmlns="http://tempuri.org/">
  <pinLoginResult>
    <username>string</username>
    <userID>guid</userID>
    <isBusinessUser>boolean</isBusinessUser>
    <functionOk>boolean</functionOk>
    <checkAmount>boolean</checkAmount>
    <refundRequested>boolean</refundRequested>
    <isPaid>boolean</isPaid>
    <duplicateUser>boolean</duplicateUser>
    <isvalid>boolean</isvalid>
    <funsdok>boolean</funsdok>
    <emailok>boolean</emailok>
    <recorddbadded>boolean</recorddbadded>
    <transisvalid>boolean</transisvalid>
    <user2isvalid>boolean</user2isvalid>
  </pinLoginResult>
 </pinLoginResponse>
 </soap:Body>
 </soap:Envelope>

但是我得到了这样的东西

anyType{userID=00000000-0000-0000-0000-000000000000;isBusinessUser=false; functionOk=false; checkAmount=false;refundRequested=false; ispaid=false; duplicateUser=false;
isValid=false; funsdok=false;emailok=false;recorddbadded=false;
transisvalid=false;user2isvalid=false;}

有没有人知道哪里出了问题...

Answer 1

终于破解了。

对我有用的是最初我在一个完整的字符串中提供数据并从 edittext 添加一些数据现在我将 pin 号分配给字符串并通过 PropertyIndo 添加这些字符串到 Soap 请求还添加了 xmlversiontag。我已经添加了工作代码。

private final String NAMESPACE = "";
private final String URL = "";
private final String SOAP_ACTION = "";
private final String METHOD_NAME = "";
String _TAG = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>";        
String pin1 = "a";
String pin2 = "b";
String pin3 = "8";
String pin4 = "d";

在我的 soapCall 方法中

StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
StrictMode.setThreadPolicy(policy);

SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

PropertyInfo _pin1 = new PropertyInfo();
_pin1.setName("pin1");
_pin1.setValue(pin1);
_pin1.setType(String.class);

PropertyInfo _pin2 = new PropertyInfo();
_pin2.setName("pin2");
_pin2.setValue(pin2);
_pin2.setType(String.class);

PropertyInfo _pin3 = new PropertyInfo();
_pin3.setName("pin3");
_pin3.setValue(pin3);
_pin3.setType(String.class);

PropertyInfo _pin4 = new PropertyInfo();
_pin4.setName("pin4");
_pin4.setValue(pin4);
_pin4.setType(String.class);


request.addProperty(_pin1);
request.addProperty(_pin2);
request.addProperty(_pin3);
request.addProperty(_pin4);

SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.setOutputSoapObject(request);        
envelope.dotNet = true;

HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);

try {
       androidHttpTransport.setXmlVersionTag(_TAG);
       androidHttpTransport.call(SOAP_ACTION, envelope);
       SoapObject response = (SoapObject)envelope.bodyIn;
       result = response.getProperty(0).toString();
       Log.i("RES", result);
    }
catch(Exception e){
       Log.i("ERR" , e.toString());
}

还要在 list 文件中添加 Internet 权限。我希望这对某人有用。