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mysql - 如果存在则选择一个值,如果不存在则选择另一个

转载 作者:行者123 更新时间:2023-11-29 00:19:52 26 4
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在这张表中:

|value_id|entity_type_id|attribute_id|store_id|entity_id|value
|9289729 |4 |62 |0 |765985 |default value
|9289730 |4 |62 |1 |765985 |value in spanish
|9289731 |4 |62 |2 |765985 |value in dutch

我需要获取 store_id 的值(可以是 1、2 或 3)或默认值 (store_id = 0),如果它不存在的话。
并且它必须包含在由多个 INNER JOINS 组成的更大查询中,到目前为止看起来像这样:

SELECT DISTINCT `p2c`.`product_id`, `name_id`.`value` AS `name`, `short_description_id`.`value` AS `short_description` FROM `catalog_category_product` AS `p2c`
INNER JOIN `catalog_product_entity_int` AS `status` ON p2c.product_id = status.entity_id AND status.value = 1
INNER JOIN `catalog_product_entity_int` AS `visibility` ON p2c.product_id = visibility.entity_id AND visibility.value = 4
INNER JOIN `catalog_product_entity_varchar` AS `name_id` ON p2c.product_id = name_id.entity_id AND name_id.attribute_id = 60
INNER JOIN `catalog_product_entity_text` AS `short_description_id` ON p2c.product_id = short_description_id.entity_id AND short_description_id.attribute_id = 62
WHERE (category_id IN ('1224'))

所以我想要的是这样的:

SELECT DISTINCT `p2c`.`product_id`, `name_id`.`value` AS `name`, `short_description_id`.`value` AS `short_description` FROM `catalog_category_product` AS `p2c`
INNER JOIN `catalog_product_entity_int` AS `status` ON p2c.product_id = status.entity_id AND status.value = 1
INNER JOIN `catalog_product_entity_int` AS `visibility` ON p2c.product_id = visibility.entity_id AND visibility.value = 4
INNER JOIN `catalog_product_entity_varchar` AS `name_id` ON p2c.product_id = name_id.entity_id AND name_id.attribute_id = 60
INNER JOIN `catalog_product_entity_text` AS `short_description_id` ON p2c.product_id = short_description_id.entity_id
AND short_description_id.attribute_id = 62
//start of not real mysql code
AND ((short_description_id.store_id = 3) IF THERE IS A VALUE FOR THIS STORE_ID
OR (short_description_id.store_id = 0) OTHERWISE)
//end of not real mysql code
WHERE (category_id IN ('1224'))

哦,如果这很重要的话,我正在使用 Zend 的 mysql。
有什么想法吗?

最佳答案

一种方法是左连接两次到 catalog_product_entity_text。一次用于 ID 0,另一个用于 ID 3,然后在您的选择中进行 COALESCE

SELECT
..
COALESCE(`short_description_id`.`value` , `short_description_id_DEFAULT`.`value`) AS `short_description`
..
FROM
...

LEFT JOIN `catalog_product_entity_text` AS `short_description_id`
ON p2c.product_id = short_description_id.entity_id
AND short_description_id.attribute_id = 62
AND (short_description_id.store_id = 3)

LEFT JOIN `catalog_product_entity_text` AS `short_description_id_DEFAULT`
ON p2c.product_id = short_description_id.entity_id
AND short_description_id.attribute_id = 62
AND (short_description_id.store_id = 0)

关于mysql - 如果存在则选择一个值,如果不存在则选择另一个,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21438157/

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