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ios - 如何使用 post 方法从登录功能将 JSON 数据传递到另一个 View Controller ?

转载 作者:行者123 更新时间:2023-11-29 00:18:07 24 4
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我在另一个 View Controller 中有空白数据,我可以在 TableView Controller 之间传递数据,但是我在解析来自登录方法的数据并从 JSON 传递访问 token 或用户名时遇到问题?

 @IBOutlet weak var username_textfield: UITextField!
@IBOutlet weak var password_textfield: UITextField!
var logindata : [Login] = []
var myResponse : JSON = nil
func getlogin(){
let headers = [
"Content-Type": "application/x-www-form-urlencoded"
]
let parameters = [

"UserName": username_textfield.text! as String,
"Password": password_textfield.text! as String,
"grant_type": "password",
]


// let url = NSURL(string: "http://192.168.100.5:84/Token")!
Alamofire.request("http://192.168.100.5:84/Token", method: .post, parameters: parameters, encoding: URLEncoding.httpBody, headers: headers).responseJSON { (response:DataResponse<Any>) in

switch(response.result) {
case.success(let data):
print("success",data)
let statusCode = (response.response?.statusCode)!
if statusCode == 200{
self.view.makeToast(message: "Welcome !!")
self.performSegue(withIdentifier: "mainview", sender: self)

}else{
self.view.makeToast(message: "Username or password invalid")
}
self.myResponse = JSON(data)
let login = Login(loginJson: self.myResponse)
DispatchQueue.main.async(execute: { () -> Void in
self.performSegue(withIdentifier: "pass_data", sender: login)
})


case.failure(let error):
print("Not Success",error)
}

}
}

将数据传递给另一个 View Controller

    override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if segue.identifier == "pass_data" {
if let eventsVC = segue.destination as? MenuDrawerViewController,
let loginData = sender as? Login {
eventsVC.login_details = loginData
}
}
}

我有模型课

class Login{

var access_token = String()
var token_type = String()
var expire_in = String()
var username = String()
var masterid = String()
var name = String()
var access = String()
var issued = String()
var expries = String()

init(loginJson:JSON){
self.access_token = loginJson["access_token"].stringValue
self.token_type = loginJson["token_type"].stringValue
self.expire_in = loginJson["expires_in"].stringValue
self.username = loginJson["userName"].stringValue
self.masterid = loginJson["MasterID"].stringValue
self.name = loginJson["Name"].stringValue
self.access = loginJson["Access"].stringValue
self.issued = loginJson[".issued"].stringValue
self.expries = loginJson[".expires"].stringValue
}


}

在第二个 View Controller 中我有这样的调用类

class MenuDrawerViewController: UIViewController {
var login_details : Login?
override func viewDidLoad() {
super.viewDidLoad()



titlename_text.text = login_details?.name
// Do any additional setup after loading the view.
}
}

I m a bit confused where I'm getting wrong or I'm doing it in wrong way, how it can be solved?

我想通过导航 Controller 传递数据并且不使用导航 Controller 传递数据所以我尝试传递这个函数并且它在“if let detailController”条件下给我错误

override  func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if segue.identifier == "dashboard" {
let navController = segue.destination as! UINavigationController
if let detailController = navController.topViewController as! ViewController,
let loginData = sender as? Login {
detailController.login_details = loginData
}
}
}

最佳答案

For loop 这里是不必要的,因为你没有得到登录数据数组你需要的是直接使用 self.myResponse 来制作 Login< 的对象。此外,您使用不同的标识符执行 segue 两次,使用相应的目标 Controller 对特定标识符执行 segue。

Alamofire.request("http://192.168.100.5:84/Token", method: .post, parameters: parameters, encoding:  URLEncoding.httpBody, headers: headers).responseJSON { (response:DataResponse<Any>) in

switch(response.result) {
case.success(let data):
print("success",data)
let statusCode = (response.response?.statusCode)!
if statusCode == 200{
self.view.makeToast(message: "Welcome !!")
}else{
self.view.makeToast(message: "Username or password invalid")
}
self.myResponse = JSON(data)
let login = Login(loginJson: self.myResponse)
DispatchQueue.main.async(execute: { () -> Void in
self.performSegue(withIdentifier: "pass_data", sender: login)
})
case.failure(let error):
print("Not Success",error)
}
}

现在让你的 prepareForSegue 像这样

override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
if segue.identifier == "pass_data" {
if let eventsVC = segue.destination as? MenuDrawerViewController,
let loginData = sender as? Login {
eventsVC.login_details = loginData
}
}
}

关于ios - 如何使用 post 方法从登录功能将 JSON 数据传递到另一个 View Controller ?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44794383/

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