android - HTTPRequest:setEntity 不起作用

Question

在我的 android 应用程序中，我试图通过后请求从我的服务器获取(在异步任务中)一个 json 字符串:

        ...

        HttpClient httpClient = new DefaultHttpClient();
        CookieStore cookieStore = new BasicCookieStore();
        HttpContext httpContext = new BasicHttpContext();
        httpContext.setAttribute(ClientContext.COOKIE_STORE, cookieStore);


        CookieSyncManager.createInstance(getApplicationContext());
        CookieManager cookieManager = CookieManager.getInstance();
        String cookies = cookieManager.getCookie("www.myExample.com");

        HttpPost post = new HttpPost("www.myExample.com/api/");

        post.setHeader("Referer", "https://www.myExample.com/");
        post.setHeader("X-Requested-With", "XMLHttpRequest");
        post.setHeader("Cookie", cookies);

        Pattern pattern = Pattern.compile("csrftoken=(.*?);");
        Matcher matcher = pattern.matcher(cookies);
        String csrftoken = "";
        if (matcher.find())
        {
            csrftoken = matcher.group(1);
        }

        post.setHeader("X-CSRFToken", csrftoken);

        >> List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(1);
        nameValuePairs.add(new BasicNameValuePair("output_format", "json"));
        nameValuePairs.add(new BasicNameValuePair("plain", "true"));


        try {
            post.setEntity(new UrlEncodedFormEntity(nameValuePairs,"UTF-8")); <<

            HttpResponse response = httpClient.execute(post);
            HttpEntity entity = response.getEntity();
            InputStream content = entity.getContent();

            BufferedReader reader = new BufferedReader(new InputStreamReader(content));

            String result, line = reader.readLine();
            result = line;

            while((line = reader.readLine()) != null) {
                result += line;
            }

            if (result != null) {
                try {
                    JSONObject jObj = new JSONObject(result);

                } catch (JSONException e) {
                   e.printStackTrace();
                }
            }

        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
        } catch (IOException e) {
            Log.d("result", "not");
            Log.d("result", e.toString());
            e.printStackTrace();
        }

        ...

在我的例子中，实体的配置似乎失败了，我总是得到结果，就好像我会在没有实体的情况下发送请求，并带有他重要的 nameValuePairs。我用 >> <<.

标记了相关行

Answer 1

将您的代码更新为要发布的代码段

   public String doInBackground(....){  

    DefaultHttpClient httpClient = new DefaultHttpClient();
    String jsonString = "{\"example\": \"go\"}";
            String url = "www.myExample.com/api/";
            HttpPost    httpReq = new HttpPost(url );
            httpReq.setHeader("Accept", "application/json");
            httpReq.setHeader("Content-type", "application/json");
            StringEntity se = new StringEntity(jsonString, "UTF-8");
            httpReq.setEntity(se);
            Log.e("Invoking Post API", ((HttpPost) httpReq).getURI().toString());

            HttpResponse response = httpClient.execute(((HttpPost) httpReq));
            String result = EntityUtils.toString(response.getEntity());

            return result;
    }

和这个要获取的 fragment

公共(public)字符串 doInBackground(....){

DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet httpReq = new HttpGet("www.myExample.com/api/");
    HttpResponse response = httpClient.execute(httpReq);
    String responseText = EntityUtils.toString(response.getEntity());
    result = responseText;
        return result;
}