ios - 无法将类型 '[UIColor]' 的值转换为预期参数类型 'NSUIColor' (又名 'UIColor' )

Question

我想在饼图中提供自定义颜色(使用图表 Pane )。但是为此，setColors([NSUIColor]) 中的数组需要 NSUIColor 格式的颜色数组，我有颜色的十六进制代码。如何使用十六进制代码在饼图中实现自定义颜色？

我的代码功能:

func pieChartUpdate ()
{
    //future home of pie chart code

    let entry1 = PieChartDataEntry(value: Double(10), label: "Morning")
    let entry2 = PieChartDataEntry(value: Double(20), label: "Evening")
    let entry3 = PieChartDataEntry(value: Double(30), label: "Midday")
    let entry4 = PieChartDataEntry(value: Double(40), label: "Before Bed")
    let dataSet = PieChartDataSet(values: [entry1, entry2, entry3, entry4], label: "Widget Types")
    let data = PieChartData(dataSet: dataSet)
    pieChartTime.data = data
    pieChartTime.chartDescription?.text = "Share of Widgets by Type"

    //All other additions to this function will go here

    dataSet.setColors(TimeColorString)
    dataSet.valueColors = [UIColor.black]


    //This must stay at end of function
    pieChartTime.notifyDataSetChanged()

}

颜色代码数组:

let TimeColorString = [UIColor.init(hex: "3366cc"),UIColor.init(hex: "ff9900"),UIColor.init(hex: "dc3912"),UIColor.init(hex: "109618")]

我用来将 Hexcode 转换为 UIColor 的扩展是:

//To convert hexcode into UI Color
extension UIColor {
convenience init(hex: String) {
    let scanner = Scanner(string: hex)
    scanner.scanLocation = 0

    var rgbValue: UInt64 = 0

    scanner.scanHexInt64(&rgbValue)

    let r = (rgbValue & 0xff0000) >> 16
    let g = (rgbValue & 0xff00) >> 8
    let b = rgbValue & 0xff

    self.init(
        red: CGFloat(r) / 0xff,
        green: CGFloat(g) / 0xff,
        blue: CGFloat(b) / 0xff, alpha: 1
    )
    }
}

Answer 1

首先创建 NSUIColor 数组，然后按如下方式使用它:

let TimeColorString = [NSUIColor(cgColor: UIColor(hex: "#00a8e1").cgColor)]
dataSet.colors = TimeColorString