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android - Renderscript 中的直方图匹配

转载 作者:行者123 更新时间:2023-11-29 00:08:51 24 4
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为了对齐两个灰度图像的强度值(作为进一步处理的第一步),我编写了一个 Java 方法:

  1. 将两个图像的位图转换为两个包含位图强度的 int[] 数组(我在这里只取红色分量,因为它是灰度,即 r=g=b ) .

    public static int[] bmpToData(Bitmap bmp){
    int width = bmp.getWidth();
    int height = bmp.getHeight();
    int anzpixel = width*height;
    int [] pixels = new int[anzpixel];
    int [] data = new int[anzpixel];
    bmp.getPixels(pixels, 0, width, 0, 0, width, height);
    for (int i = 0 ; i < anzpixel ; i++) {
    int p = pixels[i];
    int r = (p & 0xff0000) >> 16;
    //int g = (p & 0xff00) >> 8;
    //int b = p & 0xff;
    data[i] = r;
    }
    return data;
    }
  2. 将位图 2 的累积强度分布与位图 1 的强度分布对齐

        //aligns the intensity distribution of a grayscale picture moving    (given by int[] //data2) the the intensity distribution of a reference picture fixed (given by // int[] data1)
    public static int[] histMatch(int[] data1, int[] data2){

    int anzpixel = data1.length;
    int[] histogram_fixed = new int[256];
    int[] histogram_moving = new int[256];
    int[] cumhist_fixed = new int[256];
    int[] cumhist_moving = new int[256];
    int i=0;
    int j=0;

    //read intensities of fixed und moving in histogram
    for (int n = 0; n < anzpixel; n++) {
    histogram_fixed[data1[n]]++;
    histogram_moving[data2[n]]++;
    }

    // calc cumulated distributions
    cumhist_fixed[0]=histogram_fixed[0];
    cumhist_moving[0]=histogram_moving[0];
    for ( i=1; i < 256; ++i ) {
    cumhist_fixed[i] = cumhist_fixed[i-1]+histogram_fixed[i];
    cumhist_moving[i] = cumhist_moving[i-1]+histogram_moving [i];
    }

    // look-up-table lut[]. For each quantile i of the moving picture search the
    // value j of the fixed picture where the quantile is the same as that of moving
    int[] lut = new int[anzpixel];
    j=0;
    for ( i=0; i < 256; ++i ){
    while(cumhist_fixed[j]< cumhist_moving[i]){
    j++;
    }

    // check, whether the distance to the next-lower intensity is even lower, and if so, take this value
    if ((j!=0) && ((cumhist_fixed[j-1]- cumhist_fixed[i]) < (cumhist_fixed[j]- cumhist_fixed[i]))){
    lut[i]= (j-1);
    }
    else {
    lut[i]= (j);
    }
    }

    // apply the lut[] to moving picture.
    i=0;
    for (int n = 0; n < anzpixel; n++) {
    data2[n]=(int) lut[data2[n]];
    }
    return data2;
    }
  3. int[] 数组转换回位图。

    public static Bitmap dataToBitmap(int[] data, int width, int heigth) {
    int index=0;
    Bitmap bmp = Bitmap.createBitmap(width, heigth, Bitmap.Config.ARGB_8888);
    for (int x = 0; x < width; x++) {
    for (int y = 0; y < heigth; y++) {
    index=y*width+x;
    int c = data[index];
    bmp.setPixel(x,y,Color.rgb(c, c, c));
    }
    }
    return bmp;
    }

虽然核心过程 2) 简单且快速,但转换步骤 1) 和 3) 的效率相当低。在 Renderscript 中完成所有事情会更酷。但是,老实说,由于缺少文档,我完全迷失了这样做,虽然有许多关于 Renderscript 可以执行的令人印象深刻的示例,但我看不到从这些可能性中受益的方法(没有书籍,没有文档)。非常感谢任何建议!

最佳答案

首先,使用 Android Studio“导入示例...”并选择基本渲染脚本。这将为您提供一个我们现在要修改的工作项目。

首先,让我们向 MainActivity 添加更多 Allocation 引用。我们将使用它们在 Java 和 Renderscript 之间传递图像数据、直方图和 LUT。

private Allocation mInAllocation;
private Allocation mInAllocation2;
private Allocation[] mOutAllocations;
private Allocation mHistogramAllocation;
private Allocation mHistogramAllocation2;
private Allocation mLUTAllocation;

然后在 onCreate() 加载另一个图像,您还需要将其添加到/res/drawables/。

    mBitmapIn2 = loadBitmap(R.drawable.cat_480x400);

createScript() 中创建额外的分配:

    mInAllocation2 = Allocation.createFromBitmap(mRS, mBitmapIn2);
mHistogramAllocation = Allocation.createSized(mRS, Element.U32(mRS), 256);
mHistogramAllocation2 = Allocation.createSized(mRS, Element.U32(mRS), 256);
mLUTAllocation = Allocation.createSized(mRS, Element.U32(mRS), 256);

现在是主要部分(在 RenderScriptTask 中):

            /*
* Invoke histogram kernel for both images
*/
mScript.bind_histogram(mHistogramAllocation);
mScript.forEach_compute_histogram(mInAllocation);

mScript.bind_histogram(mHistogramAllocation2);
mScript.forEach_compute_histogram(mInAllocation2);


/*
* Variables copied verbatim from your code.
*/
int []histogram_fixed = new int[256];
int []histogram_moving = new int[256];
int[] cumhist_fixed = new int[256];
int[] cumhist_moving = new int[256];
int i=0;
int j=0;

// copy computed histograms to Java side
mHistogramAllocation.copyTo(histogram_fixed);
mHistogramAllocation2.copyTo(histogram_moving);

// your code again...
// calc cumulated distributions
cumhist_fixed[0]=histogram_fixed[0];
cumhist_moving[0]=histogram_moving[0];

for ( i=1; i < 256; ++i ) {
cumhist_fixed[i] = cumhist_fixed[i-1]+histogram_fixed[i];
cumhist_moving[i] = cumhist_moving[i-1]+histogram_moving [i];
}

// look-up-table lut[]. For each quantile i of the moving picture search the
// value j of the fixed picture where the quantile is the same as that of moving
int[] lut = new int[256];
j=0;
for ( i=0; i < 256; ++i ){
while(cumhist_fixed[j]< cumhist_moving[i]){
j++;
}

// check, whether the distance to the next-lower intensity is even lower, and if so, take this value
if ((j!=0) && ((cumhist_fixed[j-1]- cumhist_fixed[i]) < (cumhist_fixed[j]- cumhist_fixed[i]))){
lut[i]= (j-1);
}
else {
lut[i]= (j);
}
}

// copy the LUT to Renderscript side
mLUTAllocation.copyFrom(lut);
mScript.bind_LUT(mLUTAllocation);

// Apply LUT to the destination image
mScript.forEach_apply_histogram(mInAllocation2, mInAllocation2);


/*
* Copy to bitmap and invalidate image view
*/
//mOutAllocations[index].copyTo(mBitmapsOut[index]);

// copy back to Bitmap in preparation for viewing the results
mInAllocation2.copyTo((mBitmapsOut[index]));

注意事项:

  • 在您的代码部分,我还修复了 LUT 分配大小 - 只需要 256 个位置,
  • 如您所见,我将累积直方图和 LUT 的计算留在了 Java 端。由于数据依赖性和计算规模小,这些很难有效地并行化,但考虑到后者,我认为这不是问题。

最后是 Renderscript 代码。唯一不明显的部分是使用 rsAtomicInc() 来增加直方图 bin 中的值 - 这是必要的,因为可能有许多线程试图同时增加同一个 bin。

#pragma version(1)
#pragma rs java_package_name(com.example.android.basicrenderscript)
#pragma rs_fp_relaxed

int32_t *histogram;
int32_t *LUT;

void __attribute__((kernel)) compute_histogram(uchar4 in)
{
volatile int32_t *addr = &histogram[in.r];
rsAtomicInc(addr);
}

uchar4 __attribute__((kernel)) apply_histogram(uchar4 in)
{
uchar val = LUT[in.r];
uchar4 result;
result.r = result.g = result.b = val;
result.a = in.a;

return(result);
}

关于android - Renderscript 中的直方图匹配,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/31757109/

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