ios - 提取每秒抽动的分钟形式 NSTimer

Question

timer = [NSTimer scheduledTimerWithTimeInterval:1.0 target:self selector:@selector(myMethod) userInfo:nil repeats:YES];

-(void)myMethod {
//my every second requirment

//my every minute requirment
}

我的计时器每秒都在抽动，这是我的要求，但我还有另一个要求，例如，当我的应用程序在上午 10:05:30 启动时，我想在 10:06:00 时触发一些代码，并在 10:00 时再次触发: 07:00 继续。

我想这样做

date1 = dateFormatter ... date // this will give 10:05:30

date2 = dateFormatter ... date // this will give 10:05:00
date2 = addition of minute // this will give 10:06:00

and finally date1 compare date2 == descending // means it currently 10:06:00

但对我来说这不是一个好的解决方案，有没有更好的解决方案？

Answer 1

此解决方案效率更高，但请考虑 a tolerance of the NSTimer

@interface ViewController ()
@property (nonatomic, assign) NSInteger timerMinuteAddition;
@end

@implementation ViewController

- (void)yourScope {
    // Here you compute the initial addition to the full minute
    NSDate *currentDate = [NSDate new];
    NSCalendar *calendar = [NSCalendar currentCalendar];
    NSDateComponents *components = [calendar components:NSCalendarUnitSecond fromDate:currentDate];
    self.timerMinuteAddition = 60 - [components second];

    timer = [NSTimer scheduledTimerWithTimeInterval:1.0 target:self selector:@selector(myMethod) userInfo:nil repeats:YES];
}

- (void)myMethod {
    // your every second requirment

    self.timerMinuteAddition--;
    if (self.timerMinuteAddition == 0) {
        // your every minute requirment

        self.timerMinuteAddition = 60;
    }
}