android - 如何从另一个 IntentService 中的 IntentService 接收值？

Question

我有这个 IntentService (HttpService)，它从网络服务中获取原始 json 数据:

public class HttpService extends IntentService {

    public static final String BROADCAST_ACTION = "com.example.HttpService";

    public HttpService() {
        super("HttpService");
    }

    @Override
    protected void onHandleIntent(Intent intent) {

        //code to get a String with jsonData


         //Then I send a broadcast
         Intent broadcastHttpResponseIntent = new Intent();
         broadcastHttpResponseIntent.setAction(BROADCAST_ACTION);
         broadcastHttpResponseIntent.putExtra("jsonData", jsonData);

         sendBroadcast(broadcastHttpResponseIntent);

    }
}

现在从使用 HttpService 的 IntentService 我正在尝试获取广播:

public class RestaurantModel extends IntentService {

    public static final String BROADCAST_ACTION = "com.example.RestaurantModel";

    public RestaurantModel() {
        super("RestaurantModel");
    }

    @Override
    protected void onHandleIntent(Intent intent) {
        Log.v("RestaurantModel", "onHandleIntent");

        BroadcastReceiver httpBroadcastReceiver = new BroadcastReceiver() {
            @Override
            public void onReceive(Context context, Intent intent) {
                Log.v("RestaurantModel", "onReceive");

                String jsonResponse = intent.getStringExtra("jsonData");

            }
        };

        Intent getRestaurantsJsonIntent = new Intent(RestaurantModel.this, HttpService.class);
        getRestaurantsJsonIntent.putExtra("urlRestaurants", intent.getStringExtra("urlRestaurants"));
        startService(getRestaurantsJsonIntent);

        registerReceiver(httpBroadcastReceiver, new IntentFilter(HttpService.BROADCAST_ACTION));
    }
}

所以我收到了这个错误:

RestaurantModel has leaked IntentReceiver com.example.RestaurantModel$1@42374590 that was originally registered here. Are you missing a call to unregisterReceiver()?

所以我尝试取消注册接收者，但它似乎需要一个上下文来取消注册接收者。

如何从一个 IntentService 接收值到另一个 IntentService？

Answer 1

最佳答案是:只有一个IntentService。

下一个最佳答案是:完全摆脱广播的东西，让第一个 IntentService 调用 startService() 来启动第二个 IntentService 。