ios - 从 NSObject 类创建数组

Question

我有一个包含 3 个属性的 NSObject 类调用 Details。

 @interface Details : NSObject

@property (nonatomic, nonnull, strong) UIImage *image; 
@property (nonatomic, assign) NSInteger number; 
@property (nonatomic, nonnull, strong) NSString *details;

- (NSDictionary *_Nonnull)getMappedDictionary; @end

这个类的实现是

@interface Details()
@property (nonatomic, nonnull) NSString *imageFormat;
@property (nonatomic, nonnull) NSData *imageData;
@end

@implementation Details

- (instancetype)init {
    if (self = [super init]) {
        _imageFormat = @"jpg";
    }
    return self;
}

- (NSData *)imageData {
    if (!_imageData) {
        _imageData = UIImageJPEGRepresentation(self.image, 1.0);
    }
    return _imageData;
}

- (NSInteger)number {
    return _number;
}

- (NSString *)details {
    return _details;
}

- (NSString *)getImageBase64 {
    NSString *base64String = @"";
    base64String = [self.imageData base64EncodedStringWithOptions:kNilOptions];
    return base64String;
}

static id ObjectOrNull(id object) {
    return object ?: [NSNull null];
}

- (NSDictionary *)getMappedDictionary {
    return @{ImageKey : ObjectOrNull([self getImageBase64]), NumberKey : @(_number), DetailKey : _details};
}

在另一个调用 Request Class 的类中，我想创建一个数组来保存 Details 类的属性(图像、数字、详细信息)

- (NSMutableSet<Details *> *)details {
    if (!_details) {
        _details = [NSMutableSet new];
    }
    return _dDetails;
}

- (NSArray *)getMappedActionDetails {
    NSMutableArray *details = [NSMutableArray new];
    for (Details *detail in self.details) {
        [details addObject:[detail getMappedDictionary]];
    }
    return details;
}

但我无法将此类的属性作为数组...我在这里缺少什么？任何帮助都是完美的!谢谢

Answer 1

 -[__NSPlaceholderDictionary initWithObjects:forKeys:count:]: attempt to insert nil object from objects[0]'

意味着你用 nil 创建了一个字典。objects[0] 意味着你的拳头对象是零。所以我想当你用这个创建字典时。

- (NSDictionary *)getMappedDictionary {
     return @{ImageKey : ObjectOrNull([self getImageBase64]), NumberKey : @(_number), DetailKey : _details};
}

ObjectOrNull([self getImageBase64]) 返回 nil。