mysql - 嵌套查询返回值

Question

我有一个像这样的表 order_details

 id |  SKU  |  quantity_purchased | discount_price
---------------------------------------------------
1   | abc   |   1                 |     10.0
2   | abc   |   90                |     00
2   | abc   |   9                 |     00
3   | xyz   |   1                 |     50.0
3   | xyz   |   2                 |     50.0
4   | xyz   |   100               |     00
4   | xyz   |   100               |     00
-----------------------------------------------

我的查询是

select 
(select sum(quantity_purchased)  from order_details where discount_price > 0.00) as qty_discount,
(select sum(quantity_purchased)  from order_details where discount_price = 0.00)as qty_original,
sku
from order_details
GROUP BY sku

我需要的结果是

  SKU   |  quantity_original | quantity_discount
---------------------------------------------------
 abc    |   1                 |     99
 xyz    |   3                 |     200
-----------------------------------------------

也就是说，我在计算后需要两列相同的 sku，

我无法建立逻辑，我尝试在嵌套查询中使用 GROUP BY，但它不起作用...非常感谢任何帮助..谢谢

更新:尝试通过此操作但仍然失败，

select 
(select sum(quantity_purchased)  from order_details where discount_price > 0.00 ) as qty_discount,
(select sum(quantity_purchased)  from order_details where discount_price = 0.00 )as qty_original,
sku
from order_details
where sku = (select distinct sku from order_details)
GROUP BY sku

Answer 1

您可以为此使用条件聚合:

select sku, 
       sum(case when discount_price != 0 then quantity_purchased 
                else 0 
           end) quantity_original,
       sum(case when discount_price = 0 then quantity_purchased 
                else 0 
           end) quantity_discount
from order_details
group by sku

• SQL Fiddle Demo

---

Results:

| SKU | quantity_original | quantity_discount |
|-----|-------------------|-------------------|
| abc |                 1 |                99 |
| xyz |                 3 |               200 |