php - 数据库查询结果codeigniter后无法调用php函数

Question

请看下面的代码

//--Sec A--
$query = $this->db->insert('test',$insert_data);
$data['test_data'] = $query->result();

// --Sec B--- code to get inserted row

$this->addPanels($panArr,$job_Id,$test_Id);//$test_Id is result of Sec B

echo json_encode($data);//Result of Sec A

我无法理解为什么我无法获得 addPanels() 的结果

Answer 1

//--Sec A--
$query = $this->db->insert('test',$insert_data);
$data['test_data'] = $query->result();

//The insert ID number when performing database inserts.
$test_Id = $this->db->insert_id();

// --Sec B--- code to get inserted row

$this->addPanels($panArr,$job_Id,$test_Id);//$test_Id is result of Sec B

echo json_encode($data);//Result of Sec A