php - 如果图像数组为空，则显示替代图像

Question

我为每个在我的网站上有个人资料的用户创建了一个画廊页面。我希望画廊从数据库中提取图像并在适当的地方使用它们 - 我有这个工作。但是，当没有要显示的图像时，我想显示五个带有“即将显示图像”占位符的 block 。

如果 foreach 数组为空，我如何调整以下 PHP 代码以显示占位符？目前，如果数据库中不存在任何图像，则图库空间中不会显示任何内容。

<?php foreach($galleryphotos as $galleryphoto): ?>
        <?php if(!empty($galleryphoto['galleryphoto_file'])){ ?>
        <div class="csmx-gallery-item csmx-isotope-item col-xs-12 col-sm-6 grid-sizer post-324 portfolio type-portfolio status-publish has-post-thumbnail hentry portfolio-category-france" id="gallery-1928">
            <figure>
                <a class="csmx-media " href="<?php echo $SITE_URL; ?>media/gallery-photos/<?php echo htmlentities($galleryphoto['galleryphoto_file'], ENT_QUOTES, 'UTF-8'); ?>" title="Sarah">
                    <img src="<?php echo $SITE_URL; ?>media/gallery-photos/<?php echo htmlentities($galleryphoto['galleryphoto_file'], ENT_QUOTES, 'UTF-8'); ?>" alt="Sarah">
                    <span class="overlay-background"></span>

                        <div class="overlay-caption">
                            <i class="fa fa-picture-o" aria-hidden="true"></i>
                            <!--<h3>Sarah</h3>-->
                            <!--<p>Contrary to popular belief, Lorem Ipsum is not simply random...</p>-->
                        </div>
                </a>
            </figure>
        </div>
        <?php } ?>
        <?php endforeach; ?>

包含 Marco 提供的 IF ELSE 语句的代码；

<?php foreach($galleryphotos as $galleryphoto): ?>
        <?php if(!empty($galleryescortphoto['galleryphoto_file'])){ ?>
        <div class="csmx-gallery-item csmx-isotope-item col-xs-12 col-sm-6 grid-sizer post-324 portfolio type-portfolio status-publish has-post-thumbnail hentry portfolio-category-france" id="gallery-1928">
            <figure>
                <a class="csmx-media " href="<?php echo $SITE_URL; ?>media/gallery-photos/<?php echo htmlentities($galleryphoto['galleryphoto_file'], ENT_QUOTES, 'UTF-8'); ?>" title="Sarah">
                    <img src="<?php echo $SITE_URL; ?>media/gallery-photos/<?php echo htmlentities($galleryphoto['galleryphoto_file'], ENT_QUOTES, 'UTF-8'); ?>" alt="Sarah">
                    <span class="overlay-background"></span>

                        <div class="overlay-caption">
                            <i class="fa fa-picture-o" aria-hidden="true"></i>
                            <!--<h3>Sarah</h3>-->
                            <!--<p>Contrary to popular belief, Lorem Ipsum is not simply random...</p>-->
                        </div>
                </a>
            </figure>
        </div>
        <?php } else { ?>
            <!-- Add your placeholder image -->
            <div class="csmx-gallery-item csmx-isotope-item col-xs-12 col-sm-6 grid-sizer post-324 portfolio type-portfolio status-publish has-post-thumbnail hentry portfolio-category-france" id="gallery-1928">
            <figure>
                <a class="csmx-media " href="" title="Sarah">
                    <img src="<?php echo $SITE_URL; ?>media/gallery-photos/no-photo.png" alt="Sarah">
                    <span class="overlay-background"></span>

                        <div class="overlay-caption">
                            <i class="fa fa-picture-o" aria-hidden="true"></i>
                            <!--<h3>Sarah</h3>-->
                            <!--<p>Contrary to popular belief, Lorem Ipsum is not simply random...</p>-->
                        </div>
                </a>
            </figure>
        </div>
        <?php } ?>
        <?php endforeach; ?>

使用 Kiran 的示例更新了代码 - 这不会显示存储的图像，而是显示占位符，即使存在图像值也是如此；

<?php if(empty($galleryphotos)) $galleryphotos[0]['galleryphoto_file'] = "image-not-available.jpg";
    foreach($galleryphotos as $galleryphoto): ?>
    <div class="csmx-gallery-item csmx-isotope-item col-xs-12 col-sm-6 grid-sizer post-324 portfolio type-portfolio status-publish has-post-thumbnail hentry portfolio-category-france" id="gallery-1928">
        <figure>
            <a class="csmx-media " href="<?php echo $SITE_URL; ?>media/gallery-photos/<?php echo htmlentities($galleryphoto['galleryphoto_file'], ENT_QUOTES, 'UTF-8'); ?>" title="Sarah">
                <img src="<?php echo $SITE_URL; ?>media/gallery-photos/<?php echo htmlentities($galleryphoto['galleryphoto_file'], ENT_QUOTES, 'UTF-8'); ?>" alt="Sarah">
                <span class="overlay-background"></span>

                    <div class="overlay-caption">
                        <i class="fa fa-picture-o" aria-hidden="true"></i>
                        <!--<h3>Sarah</h3>-->
                        <!--<p>Contrary to popular belief, Lorem Ipsum is not simply random...</p>-->
                    </div>
            </a>
        </figure>
    </div>
    <?php endforeach; ?>

Answer 1

我想您想在图库为空时显示占位符照片。如果是这样，那么您可能想这样做:

<?php if(empty($galleryphotos)) $galleryphotos[0]['galleryphoto_file'] = "no-photo.png";
    foreach($galleryphotos as $galleryphoto): ?>
    <div class="csmx-gallery-item csmx-isotope-item col-xs-12 col-sm-6 grid-sizer post-324 portfolio type-portfolio status-publish has-post-thumbnail hentry portfolio-category-france" id="gallery-1928">
        <figure>
            <a class="csmx-media " href="<?php echo $SITE_URL; ?>media/gallery-photos/<?php echo htmlentities($galleryphoto['galleryphoto_file'], ENT_QUOTES, 'UTF-8'); ?>" title="Sarah">
                <img src="<?php echo $SITE_URL; ?>media/gallery-photos/<?php echo htmlentities($galleryphoto['galleryphoto_file'], ENT_QUOTES, 'UTF-8'); ?>" alt="Sarah">
                <span class="overlay-background"></span>

                    <div class="overlay-caption">
                        <i class="fa fa-picture-o" aria-hidden="true"></i>
                        <!--<h3>Sarah</h3>-->
                        <!--<p>Contrary to popular belief, Lorem Ipsum is not simply random...</p>-->
                    </div>
            </a>
        </figure>
    </div>
    <?php endforeach; ?>

上述代码的变化:

1. 第一行检查 $galleryphotos 数组是否为空，如果为真，则向其添加一个占位符。
2. 删除 if 条件，因为它是不必要的
3. 其余代码与它应该工作的一样。

更新#1:

问题可能是由于第一个 if 子句尝试将条件更改为:

if(count($galleryphotos)==0) $gallerypho...