php - 如何在每次迭代中以从上到下的方式旋转数组元素

Question

我有一个 n 大小的数组假设我的原始数组是:

array=(alpha,bravo,charlie,delta,echo,foxtrot);

我想向左旋转上面的数组前输出第一次迭代

array=(bravo,charlie,delta,echo,foxtrot,alpha); 

和第二次迭代

array=(charlie,delta,echo,foxtrot,alpha,bravo);

我想在每次迭代中都这样做，直到获得原始数组。

注意:上面的数组是我从特定查询的 MySQL 输出中获取的。所以原始数组将始终是 array=(alpha,bravo,charlie,delta,echo,foxtrot);

提前感谢您的任何建议和帮助

Answer 1

$array = array('alpha','bravo','charlie','delta','echo','foxtrot');

for($i=0; $i< count($array);$i++)
{
    $firstValue = array_shift($array);
    array_push($array, $firstValue);
    var_dump($array); //here you get your array with the first value shifted to the end of the array
}

结果:

array(6) {
  [0]=>
  string(5) "bravo"
  [1]=>
  string(7) "charlie"
  [2]=>
  string(5) "delta"
  [3]=>
  string(4) "echo"
  [4]=>
  string(7) "foxtrot"
  [5]=>
  string(5) "alpha"
}
array(6) {
  [0]=>
  string(7) "charlie"
  [1]=>
  string(5) "delta"
  [2]=>
  string(4) "echo"
  [3]=>
  string(7) "foxtrot"
  [4]=>
  string(5) "alpha"
  [5]=>
  string(5) "bravo"
}
array(6) {
  [0]=>
  string(5) "delta"
  [1]=>
  string(4) "echo"
  [2]=>
  string(7) "foxtrot"
  [3]=>
  string(5) "alpha"
  [4]=>
  string(5) "bravo"
  [5]=>
  string(7) "charlie"
}
array(6) {
  [0]=>
  string(4) "echo"
  [1]=>
  string(7) "foxtrot"
  [2]=>
  string(5) "alpha"
  [3]=>
  string(5) "bravo"
  [4]=>
  string(7) "charlie"
  [5]=>
  string(5) "delta"
}
array(6) {
  [0]=>
  string(7) "foxtrot"
  [1]=>
  string(5) "alpha"
  [2]=>
  string(5) "bravo"
  [3]=>
  string(7) "charlie"
  [4]=>
  string(5) "delta"
  [5]=>
  string(4) "echo"
}
array(6) {
  [0]=>
  string(5) "alpha"
  [1]=>
  string(5) "bravo"
  [2]=>
  string(7) "charlie"
  [3]=>
  string(5) "delta"
  [4]=>
  string(4) "echo"
  [5]=>
  string(7) "foxtrot"
}