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java - JSP在JavaEE和tomcat 9中无法指向Servlet类中的Post方法

转载 作者:行者123 更新时间:2023-11-28 23:23:15 24 4
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我在 jsp 中有以下表单,其中包含一个文本字段和一个按钮

<form action="/login.do" method="Post">
Enter
<br/><br/>
Your Name <input type="text" name="name"/>
<br/><br/>
Password <input type="text" name="password"/>
<br/><br/>
<select name="Gender">
<option value="Male">Male</option>
<option value="Female">Female</option>
</select>
<br/><br/>
<input type="submit" value="Login"/>

我的小服务程序:

@WebServlet(urlPatterns = "/login.do")
public class LoginServlet extends HttpServlet{
protected void doGet(HttpServletRequest request, javax.servlet.http.HttpServletResponse response)
throws ServletException, IOException{
request.getRequestDispatcher("/WEB-INF/view/login.jsp").forward(request, response);


}

@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String name =request.getParameter("name");
String password = request.getParameter("password");
String gender = ((String)request.getParameter("Gender")=="Female")? "Ms.":"Mr.";

if(new ValidateUser().validate(name, password)){
request.setAttribute("name", name);
request.setAttribute("password", password);
request.setAttribute("gender", gender);
request.getRequestDispatcher("/WEB-INF/view/welcome.jsp").forward(request, response);;
} else {
request.setAttribute("errorMes", "Login Failed");
request.getRequestDispatcher("/WEB-INF/view/login.jsp").forward(request, response);;
}
}

根据教程,当我在jsp页面中点击按钮时,会触发Servlet类中的doPost()方法。

但是我一直收到 HTTP 状态 404 -/login.do 错误

请帮忙! ...

我的 web.xml

<?xml version="1.0" encoding="UTF-8"?>
<!-- webapp/WEB-INF/web.xml -->
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" version="3.0">

<display-name>To do List</display-name>
<welcome-file-list>
<welcome-file>login.do</welcome-file>
</welcome-file-list>

当我运行项目时,我连接到这个 URL:http://localhost:8081/in28Minutes-first-webapp/

当我点击按钮时,我连接到这个 url:http://localhost:8081/login.do并给出“HTTP Status 404 -/login.do”错误

我试过“${pageContext.request.contextPath}/login.do”,还是报错

我有这个 pom.xml

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>

<groupId>com.in28minutes</groupId>
<artifactId>in28Minutes-first-webapp</artifactId>
<version>0.0.1-SNAPSHOT</version>
<packaging>war</packaging>

<dependencies>
<dependency>
<groupId>javax</groupId>
<artifactId>javaee-web-api</artifactId>
<version>6.0</version>
<scope>provided</scope>
</dependency>
</dependencies>

<build>
<pluginManagement>
<plugins>
<plugin>
<groupId>org.apache.maven.plugins</groupId>
<artifactId>maven-compiler-plugin</artifactId>
<version>3.2</version>
<configuration>
<verbose>true</verbose>
<source>1.7</source>
<target>1.7</target>
<showWarnings>true</showWarnings>
</configuration>
</plugin>
<plugin>
<groupId>org.apache.tomcat.maven</groupId>
<artifactId>tomcat7-maven-plugin</artifactId>
<version>2.2</version>
<configuration>
<path>/</path>
<contextReloadable>true</contextReloadable>
</configuration>
</plugin>
</plugins>
</pluginManagement>
</build>

最佳答案

我的建议是:

您应该在表单标签的操作参数中设置您在页面 localhost:8081/in28Minutes-first-webapp/login.do 上的位置,而不是 localhost:8081/login.do。尝试设置以下设置之一:action="login.do"action="localhost:8081/in28Minutes-first-webapp/login.do" action="/in28Minutes-first-webapp/login.do".

I have tried "${pageContext.request.contextPath}/login.do", it still gives the error

你给定的错误如何? ${pageContext.request.contextPath} 的值如何?

关于java - JSP在JavaEE和tomcat 9中无法指向Servlet类中的Post方法,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40317530/

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