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java - HTML 500 Tomcat Java

转载 作者:行者123 更新时间:2023-11-28 23:22:19 25 4
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我正在尝试学习如何使用 tomcat 进行 Java Web 应用程序我有一个良好的开端,但是当我尝试加载我的 servlet 类时,出现 500 错误

我的 newPlayer.java 文件:

    package servlet;
import java.io.IOException;
import java.io.PrintWriter;


/**
* Created by kbuczynski on 24/01/17.
*/

public class newPlayer extends javax.servlet.http.HttpServlet {

protected void doPost(javax.servlet.http.HttpServletRequest request, javax.servlet.http.HttpServletResponse response) throws javax.servlet.ServletException, IOException {
}

protected void doGet(javax.servlet.http.HttpServletRequest request, javax.servlet.http.HttpServletResponse response) throws javax.servlet.ServletException, IOException {
response.setContentType("text/html");
PrintWriter out = response.getWriter();
out.print("<h1>HI</h1>");
out.flush();
}
}

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
version="3.1">
<display-name>WeBJ</display-name>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>newPlayer</servlet-name>
<servlet-class>servlet.newPlayer</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>newPlayer</servlet-name>
<url-pattern>/newPlayer</url-pattern>
</servlet-mapping>
</web-app>

错误:

exception

javax.servlet.ServletException: Error instantiating servlet class servlet.newPlayer
org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:474)
org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:79)
org.apache.catalina.valves.AbstractAccessLogValve.invoke(AbstractAccessLogValve.java:624)
org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:349)
org.apache.coyote.http11.Http11Processor.service(Http11Processor.java:495)
org.apache.coyote.AbstractProcessorLight.process(AbstractProcessorLight.java:66)
org.apache.coyote.AbstractProtocol$ConnectionHandler.process(AbstractProtocol.java:767)
org.apache.tomcat.util.net.NioEndpoint$SocketProcessor.doRun(NioEndpoint.java:1347)
org.apache.tomcat.util.net.SocketProcessorBase.run(SocketProcessorBase.java:49)
java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142)
java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617)
org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61)
java.lang.Thread.run(Thread.java:745)
root cause

java.lang.ClassNotFoundException: servlet.newPlayer
org.apache.catalina.loader.WebappClassLoaderBase.loadClass(WebappClassLoaderBase.java:1275)
org.apache.catalina.loader.WebappClassLoaderBase.loadClass(WebappClassLoaderBase.java:1109)
org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:474)
org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:79)
org.apache.catalina.valves.AbstractAccessLogValve.invoke(AbstractAccessLogValve.java:624)
org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:349)
org.apache.coyote.http11.Http11Processor.service(Http11Processor.java:495)
org.apache.coyote.AbstractProcessorLight.process(AbstractProcessorLight.java:66)
org.apache.coyote.AbstractProtocol$ConnectionHandler.process(AbstractProtocol.java:767)
org.apache.tomcat.util.net.NioEndpoint$SocketProcessor.doRun(NioEndpoint.java:1347)
org.apache.tomcat.util.net.SocketProcessorBase.run(SocketProcessorBase.java:49)
java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1142)
java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:617)
org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61)
java.lang.Thread.run(Thread.java:745)

文件结构

CLICK

我总是很乐意接受任何建议,所以请随意这样做。

最佳答案

一个好的项目结构可能是maven所遵循的:project-structure .我的 github 上有一个使用 maven 作为构建工具的小 servlet 项目:simple-servlet .

关于java - HTML 500 Tomcat Java,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41832176/

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