gpt4 book ai didi

php - 如何在php中匹配两行mysql同一个表

转载 作者:行者123 更新时间:2023-11-28 23:09:53 27 4
gpt4 key购买 nike

我有一个表,如果需要,可以通过添加按钮在其中添加行。我的数据库中有两个表 product_size 和 product_color。 Product_color 表有包含尺码 ID 的列。我正在尝试这样做,如果两个或更多行值在尺寸表中相同,例如“小”,那么它应该为所有小颜色插入相同的 size_id 到颜色表。如果有人可以,请检查我的代码并提供帮助。 product_size table

产品颜色表 enter image description here

代码:

 if (isset($_POST['submit']))
{
$con=mysqli_connect("localhost", "root", "");
mysqli_select_db($con,"login");

for ($i=0; $i<count($_POST['size']); $i++){

$size = $_POST['size'][$i];

$qry1="INSERT INTO product_size (product_size) VALUES ('$size')";

$result1=mysqli_query($con,$qry1);
$product_size_id = mysqli_insert_id($con);


$quantity = $_POST['dress_quantity'][$i];

$color = $_POST['color'][$i];

$qry2="INSERT INTO product_color (product_size_id, product_color, product_quantity) VALUES ('$product_size_id', '$color', '$quantity')";

$result2=mysqli_query($con,$qry2);
if($result2)
{
echo '<script>alert("Record Added Successfully!")</script>';
echo '<script>window.location="try.php"</script>';
}
else
{
die("Error While Adding Stock! Please Try Again.");
}
}
}

//HTML代码:

<TABLE id="dataTable">
<thead>
<tr>
<th style="text-align: center;">&nbsp;Select&nbsp;</th>
<th style="text-align: center;">&nbsp;<b>Size</b>&nbsp;</th>
<th style="text-align: center;">&nbsp;<b>Color</b>&nbsp;</th>
<th><b>Quantity</b></th>
</tr>
</thead>

<tbody>
<tr id='C1' class='customer'>
<td><input type="checkbox" name="chk"/></td>
<td><select name="size[]" id="size" required="" >
<option value="">Select Size</option></select></td>
<td>
<select name="color[]" required="" >
<option value="">Select Color</option>
<option value="Aqua">Aqua</option>
<option value="Blue">Blue</option>
<option value="Black">Black</option>
<option value="Green">Green</option>
</select></td>

<td>
<input style="width: 120px; height: 26px; " oninput="javascript: if (this.value.length > this.maxLength) this.value = this.value.slice(0, this.maxLength);" type="number" name="dress_quantity[]" class="qty1" onchange="calculate();" min="1" max="1000" maxlength="4" placeholder="Size Quantity" value="" required="">

</td>
</tr>
</tbody>
</TABLE>
<INPUT type="button" value="Add Row" onclick="addRow('dataTable')" />
<INPUT type="button" value="Delete Row" onclick="deleteRow('dataTable')" />

//HTML 表格 enter image description here

最佳答案

首先,您需要创建一个表格,其中包含您想要的所有尺寸。尺码表应该只有尺码 ID 和尺码名称,然后使用该表创建您的尺码下拉列表。

然后在您的 HTML 表格页面上执行类似的操作。

<?php
$con=mysqli_connect("localhost", "root", "");
mysqli_select_db($con,"login");

$query = mysqli_query("SELECT * FROM size");
$sizeParam = $database->query($query);
$sizeParam -> execute();
?>

然后在您的 HTML 中:

<TABLE id="dataTable">
<thead>
<tr>
<th style="text-align: center;">&nbsp;Select&nbsp;</th>
<th style="text-align: center;">&nbsp;<b>Size</b>&nbsp;</th>
<th style="text-align: center;">&nbsp;<b>Color</b>&nbsp;</th>
<th><b>Quantity</b></th>
</tr>
</thead>
<tbody>
<tr id='C1' class='customer'>
<td><input type="checkbox" name="chk"/></td>
<td>
<select name="size[]" id="size" required="" >
<option value="">Select Size</option></select></td>
<?php while($getSizeRow = $sizeParam -> fetch_assoc()){ ?>
<option id="<?php echo $getSizwRow["sizeId"]; ?>"><?php echo $getSizwRow["sizeId"]; ?></option></select>
</td>
<td>
<select name="color[]" required="" >
<option value="">Select Color</option>
<option value="Aqua">Aqua</option>
<option value="Blue">Blue</option>
<option value="Black">Black</option>
<option value="Green">Green</option>
</select></td>
<td>
<input style="width: 120px; height: 26px; " oninput="javascript: if (this.value.length > this.maxLength) this.value = this.value.slice(0, this.maxLength);" type="number" name="dress_quantity[]" class="qty1" onchange="calculate();" min="1" max="1000" maxlength="4" placeholder="Size Quantity" value="" required="">
</td>
</tr>
</tbody>
</TABLE>
<INPUT type="button" value="Add Row" onclick="addRow('dataTable')" />
<INPUT type="button" value="Delete Row" onclick="deleteRow('dataTable')" />

现在,当您接收到处理 PHP 的数据时,执行类似的操作。

if (isset($_POST['submit'])){

$con=mysqli_connect("localhost", "root", "");
mysqli_select_db($con,"login");

$quantity = $_POST['dress_quantity'];
$color = $_POST['color'];
$size = $_POST['size'];

$qry2="INSERT INTO product_color (product_size_id, product_color, product_quantity) VALUES (?, ?, ?)";
$result2= $con -> prepare($qry2);
$result2 -> bind_param(isi, $product_size_id, $color, $quantity);

if($result2 -> execute()){
echo '<script>alert("Record Added Successfully!")</script>';
echo '<script>window.location="try.php"</script>';
}else{
die("Error While Adding Stock! Please Try Again.");
}
}
}

这可能包含错误,这是基本思想,我对 mysqli_* 不是很流利,所以如果有任何错误,请告诉我以更正错误。

关于php - 如何在php中匹配两行mysql同一个表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/46274496/

27 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com