iphone - json 对象 UITableView

Question

服务器返回如下所示的json对象:大约51个对象

[{"location":"Location1","email":"sriharsha@yahoo.com","phone":"123456"},{"location":"Location2","email":"sriharsha.mandya@gmail.com","phone":"123456789"},
.
.
..
..
..51]

我想将这个值首先分配给带有电子邮件和电话号码的位置和详细 View ......

我使用的代码如下:

- (void)connectionDidFinishLoading:(NSURLConnection *)connection {
    [connection release];

    NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
    [responseData release];

    NSDictionary *dictionary = [responseString JSONValue];
    NSArray *response = [dictionary objectForKey:@"location"];

    exercises = [[NSArray alloc] initWithArray:response];
    [table reloadData];
}

我哪里错了请指教...

Answer 1

乍一看，响应字符串看起来像一个字典数组

访问数据尝试类似的东西

NSArray* arrayOfDictionaries = [responseString JSONValue];
NSDictionary* firstDictionary = [arrayOfDictionaries objectAtIndex:0];