gpt4 book ai didi

iphone - 将 UIPicker 添加到文本字段

转载 作者:行者123 更新时间:2023-11-28 23:07:33 25 4
gpt4 key购买 nike

我有一个表格 View ,我必须在某些单元格中显示文本字段。当用户单击文本字段时,我希望选择器 View 显示 0 到 99 之间的整数值。一旦用户在选择器 View 中选择了项目,就需要在该特定文本字段上显示相同的项目。任何帮助将不胜感激。

最佳答案

   -(void) viewDidLoad
{
arrayNo = [[NSMutableArray alloc] init];
[arrayNo addObject:@"1"];
[arrayNo addObject:@"2"];
[arrayNo addObject:@"3"];
// and so on....
}

将此行的目标添加到您的文本字段函数

  UITextfield *entered2;
//..... some codes
[entered2 addTarget:self action:@selector(showPicker)forControlEvents:UIControlEventEditingDidBegin];
[myview addSubview:entered2];




-(void) showPicker
{
[entered2 resignFirstResponder];
pickerView = [[UIPickerView alloc] initWithFrame:CGRectMake(0,240,220,0)];

pickerView.delegate = self;
pickerView.dataSource = self;
pickerView.showsSelectionIndicator = YES;

[self.view addSubview:pickerView];
[pickerView release];
}

- (NSInteger)pickerView:(UIPickerView *)pickerView numberOfRowsInComponent:(NSInteger)component
{
return [arrayNo count];
}
- (NSInteger)numberOfComponentsInPickerView:(UIPickerView *)pickerView {
return 1;
}
- (void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component
{
entered2.text=[arrayNo objectAtIndex:row];
[pickerView removeFromSuperview];
}
- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component
{
return [arrayNo objectAtIndex:row];
[pickerView removeFromSuperview];
}
- (CGFloat)pickerView:(UIPickerView *)pickerView widthForComponent:(NSInteger)component {
int sectionWidth = 300;
return sectionWidth;
}

关于iphone - 将 UIPicker 添加到文本字段,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9064367/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com