python - 如何在字典列表中比较键值？

Question

我在下面有这个字典列表。我想要的是搜索相同的“别名”并添加他们的分数以将它们组合成一个字典并制作一个更清晰的列表。

d=[{"alias": "2133232", "score": 144}, {"alias": "u234243", "score": 34}, {"alias": "u234243", "score": 34},{"alias": "2133232", "score": 14}, {"alias": "u234243", "score": 4}, {"alias": "u234243", "score": 344}]

输出应该是这样的:

`[{"alias": "2133232", "score": 158}, {"alias": "u234243", "score": 416}]`

Answer 1

python 2.5:

from collections import defaultdict 

h = defaultdict(int)
for i in d:
    h[i['alias']] += i['score']