iphone - 从单词对象的 NSMutableArray 中创建一个干净的单词 NSString，然后用于搜索

Question

suitsArray 是 MutableArray，当按钮处于选中状态时添加对象(单词)。

在接下来的部分中，我需要将 suitsCriteriaString 变成一个干净的字符串，其中只有一个空格将单词与 suitsArray 分隔开，这意味着没有逗号或其他符号! (用 NSSet 什么的？)

NSString *suitsCriteriaString = [NSString stringWithFormat:@"%@", suitsArray];
NSString *wineSuitsString = [wine objectForKey:@"Suits"];
NSRange range = [wineSuitsString rangeOfString:suitsCriteriaString options:NSCaseInsensitiveSearch];

然后，NSRange，如果操作正确，应该检查 suitCriteriaString 中的单词是否存在于 wineSuitsString 中。然后，应过滤结果以仅包含匹配的词!

我的搜索功能的代码如下，如果您需要更多信息来完成这项工作，请告诉我。

---

SearchViewController.h

---

#import <UIKit/UIKit.h>

@interface SearchViewController : UIViewController {

@property (nonatomic, strong) NSMutableArray *allObjectsArray;
@property (nonatomic, strong) NSMutableArray *resultObjectsArray;

@property (nonatomic, strong) NSMutableArray *suitsArray;

@property (nonatomic, retain) IBOutlet UISlider *minPrisSlider;
@property (nonatomic, retain) IBOutlet UISlider *maxPrisSlider;

-(IBAction)searchButtonPressed:(id)sender;

@end

---

SearchViewController.m:

---

填充所有对象数组:

- (void)viewDidLoad
{
[super viewDidLoad];

NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
NSString *documentsDirectory = [paths objectAtIndex:0];
NSString *path = [documentsDirectory stringByAppendingPathComponent:@"Wine.plist"];
allObjectsArray = [[NSMutableArray alloc] initWithContentsOfFile:path];
}

---

从 suitArray 添加或删除对象，我有 10 个类似这样的按钮:

-(IBAction)lambButtonPressed:(id)sender
{
if (lambButtonSelected == 0) {

    lambButtonSelected = 1;
    [suitsArray addObject:@"lamb"];

} else {

    lambButtonSelected = 0;
    [suitsArray removeObject:@"lamb"];

}
}

---

然后，将对象添加到搜索结果中:

-(IBAction)searchButtonPressed:(id)sender{  

resultObjectsArray = [NSMutableArray array];
for(NSDictionary *wine in allObjectsArray)

    {

    //String for price
    NSString *winePrice = [wine objectForKey:@"Price"];        

    /*THIS IS WHERE I'M TRYING TO CHECK IF THE WORDS IN suitsCriteriaString
    ARE EXISTING IN wineSuitsString */

    NSString *suitsCriteriaString = [NSString stringWithFormat:@"%@", suitsArray];
    NSString *wineSuitsString = [wine objectForKey:@"Suits"];
    NSRange range = [wineSuitsString rangeOfString:suitsCriteriaString options:NSCaseInsensitiveSearch];


    //THEN LAST, ADD OBJECTS WITH MATCH OF PRICE CRITERIA AND SUITS CRITERIA TO RESULTS:

    BOOL priceConditionGood = YES;
    if (minPrisSlider.value <= maxPrisSlider.value && (winePrice.floatValue < minPrisSlider.value || winePrice.floatValue > maxPrisSlider.value))
        priceConditionGood = NO;
    if (range.location != NSNotFound && priceConditionGood)
        [resultObjectsArray addObject:wine];
     }
     }

//AND PUSH RESULTS CONTROLLER:

ResultsTableViewController *nextController = [[self storyboard] instantiateViewControllerWithIdentifier:@"ResultsController"];
nextController.objectsArray = [[NSMutableArray alloc]initWithArray:resultObjectsArray];
[self.navigationController pushViewController:nextController animated:YES];
}

Answer 1

“suitsCriteriaString”不会给你你想要的。遍历“suitsArray”并比较每个单词会容易得多:

NSString *wineSuitsString = [wine objectForKey:@"Suits"];
BOOL foundMatch = true;
for (NSString *suit in suitsArray) {
  NSRange range = [wineSuitsString rangeOfString:suit options:NSCaseInsensitiveSearch];
  if (range.location == NSNotFound) {
    foundMatch = false;
    break;
  }
}