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python - pyaudio 可以同时播放两个音符吗?

转载 作者:行者123 更新时间:2023-11-28 22:50:08 30 4
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是否可以使用 pyaudio 演奏和弦?

最佳答案

当然可以!

只需生成结果并将其传递给播放器即可。

This article covers a method to do it.

以下是示例代码,以防链接中的文章发生更改或失效:

import math
import numpy
import pyaudio
import itertools
from scipy import interpolate
from operator import itemgetter

# https://davywybiral.blogspot.com/2010/09/procedural-music-with-pyaudio-and-numpy.html

class Note:

NOTES = ['c','c#','d','d#','e','f','f#','g','g#','a','a#','b']

def __init__(self, note, octave=4):
self.octave = octave
if isinstance(note, int):
self.index = note
self.note = Note.NOTES[note]
elif isinstance(note, str):
self.note = note.strip().lower()
self.index = Note.NOTES.index(self.note)

def transpose(self, halfsteps):
octave_delta, note = divmod(self.index + halfsteps, 12)S
return Note(note, self.octave + octave_delta)

def frequency(self):
base_frequency = 16.35159783128741 * 2.0 ** (float(self.index) / 12.0)
return base_frequency * (2.0 ** self.octave)

def __float__(self):
return self.frequency()


class Scale:

def __init__(self, root, intervals):
self.root = Note(root.index, 0)
self.intervals = intervals

def get(self, index):
intervals = self.intervals
if index < 0:
index = abs(index)
intervals = reversed(self.intervals)
intervals = itertools.cycle(self.intervals)
note = self.root
for i in range(index):
note = note.transpose(next(intervals))
return note

def index(self, note):
intervals = itertools.cycle(self.intervals)
index = 0
x = self.root
while x.octave != note.octave or x.note != note.note:
x = x.transpose(next(intervals))
index += 1
return index

def transpose(self, note, interval):
return self.get(self.index(note) + interval)


def sine(frequency, length, rate):
length = int(length * rate)
factor = float(frequency) * (math.pi * 2) / rate
return numpy.sin(numpy.arange(length) * factor)

def shape(data, points, kind='slinear'):
items = points.items()
sorted(items,key=itemgetter(0))
keys = list(map(itemgetter(0), items))
vals = list(map(itemgetter(1), items))
interp = interpolate.interp1d(keys, vals, kind=kind)
factor = 1.0 / len(data)
shape = interp(numpy.arange(len(data)) * factor)
return data * shape

def harmonics1(freq, length):
a = sine(freq * 1.00, length, 44100)
b = sine(freq * 2.00, length, 44100) * 0.5
c = sine(freq * 4.00, length, 44100) * 0.125
return (a + b + c) * 0.2

def harmonics2(freq, length):
a = sine(freq * 1.00, length, 44100)
b = sine(freq * 2.00, length, 44100) * 0.5
return (a + b) * 0.2

def pluck1(note):
chunk = harmonics1(note.frequency(), 2)
return shape(chunk, {0.0: 0.0, 0.005: 1.0, 0.25: 0.5, 0.9: 0.1, 1.0:0.0})

def pluck2(note):
chunk = harmonics2(note.frequency(), 2)
return shape(chunk, {0.0: 0.0, 0.5:0.75, 0.8:0.4, 1.0:0.1})

def chord(n, scale):
root = scale.get(n)
third = scale.transpose(root, 2)
fifth = scale.transpose(root, 4)
return pluck1(root) + pluck1(third) + pluck1(fifth)

root = Note('A', 3)
scale = Scale(root, [2, 1, 2, 2, 1, 3, 1])

chunks = []
chunks.append(chord(21, scale))
chunks.append(chord(19, scale))
chunks.append(chord(18, scale))
chunks.append(chord(20, scale))
chunks.append(chord(21, scale))
chunks.append(chord(22, scale))
chunks.append(chord(20, scale))
chunks.append(chord(21, scale))

chunks.append(chord(21, scale) + pluck2(scale.get(38)))
chunks.append(chord(19, scale) + pluck2(scale.get(37)))
chunks.append(chord(18, scale) + pluck2(scale.get(33)))
chunks.append(chord(20, scale) + pluck2(scale.get(32)))
chunks.append(chord(21, scale) + pluck2(scale.get(31)))
chunks.append(chord(22, scale) + pluck2(scale.get(32)))
chunks.append(chord(20, scale) + pluck2(scale.get(29)))
chunks.append(chord(21, scale) + pluck2(scale.get(28)))

chunk = numpy.concatenate(chunks) * 0.25

p = pyaudio.PyAudio()
stream = p.open(format=pyaudio.paFloat32, channels=1, rate=44100, output=1)
stream.write(chunk.astype(numpy.float32).tostring())
stream.close()
p.terminate()

here是更好的来源

关于python - pyaudio 可以同时播放两个音符吗?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23001846/

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