python，将列表转换为类似的子列表

Question

我想将名称列表转换为类似的子列表。例子

['yam-nb-109.0-8438773.i686.rpm', 'yam-nb-112.0-10561609.i686.rpm', 
 'yam-ris-105.0-7269382.i686.rpm', 'yam-ris-106.0-7451269.i686.rpm', 
 'yam-ris-107.0-7899661.i686.rpm', 'yam-ris-112.0-10577466.i686.rpm', 
 'yam-logg-110.0-9833588.i686.rpm', 'yam-logg-111.0-10278753.i686.rpm', 
 'yam-logg-99.0-5275910.i686.rpm', 'yamboard-114.0-10902994.i686.rpm', 
 'yamboard-114.0-11436227.i686.rpm']

进入

[['yam-nb-109.0-8438773.i686.rpm', 'yam-nb-112.0-10561609.i686.rpm'], 
 ['yam-ris-105.0-7269382.i686.rpm', 'yam-ris-106.0-7451269.i686.rpm', 'yam-ris-107.0-7899661.i686.rpm', 'yam-ris-112.0-10577466.i686.rpm'], 
 ['yam-logg-110.0-9833588.i686.rpm', 'yam-logg-111.0-10278753.i686.rpm', 'yam-logg-99.0-5275910.i686.rpm'],
 ['yamboard-114.0-10902994.i686.rpm', 'yamboard-114.0-11436227.i686.rpm']]

这里的任何建议都会有所帮助。

提前致谢...

Answer 1

使用 itertools.groupby :

>>> import itertools
>>>
>>> pkgs = [
...     'yam-nb-109.0-8438773.i686.rpm', 'yam-nb-112.0-10561609.i686.rpm',
...     'yam-ris-105.0-7269382.i686.rpm', 'yam-ris-106.0-7451269.i686.rpm',
...     'yam-ris-107.0-7899661.i686.rpm', 'yam-ris-112.0-10577466.i686.rpm',
...     'yam-logg-110.0-9833588.i686.rpm', 'yam-logg-111.0-10278753.i686.rpm',
...     'yam-logg-99.0-5275910.i686.rpm', 'yamboard-114.0-10902994.i686.rpm',
...     'yamboard-114.0-11436227.i686.rpm'
... ]
>>>
>>> pkg_name = lambda fn: fn.rsplit('-', 2)[0]
>>> [list(grp) for _, grp in itertools.groupby(pkgs, key=pkg_name)]
[['yam-nb-109.0-8438773.i686.rpm',
  'yam-nb-112.0-10561609.i686.rpm'],
 ['yam-ris-105.0-7269382.i686.rpm',
  'yam-ris-106.0-7451269.i686.rpm',
  'yam-ris-107.0-7899661.i686.rpm',
  'yam-ris-112.0-10577466.i686.rpm'],
 ['yam-logg-110.0-9833588.i686.rpm',
  'yam-logg-111.0-10278753.i686.rpm',
  'yam-logg-99.0-5275910.i686.rpm'],
 ['yamboard-114.0-10902994.i686.rpm',
  'yamboard-114.0-11436227.i686.rpm']]

注意

以上代码假设

• 您希望按包名对文件名进行分组
• 文件名已排序
• 包名相同后的版本号格式(package_name-version-version2.i686.rpm)