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python - 在Python2.7中实现Barrier

转载 作者:行者123 更新时间:2023-11-28 22:47:11 24 4
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我使用 Barriers 在 Python3 中实现了这段代码。我想在 Python2.7 中获得相同的功能,但我不知道要使用哪个同步原语,因为 Barriers 在 Python2.7 中不存在

import threading
import time
from threading import Thread,Barrier

b = Barrier(2, timeout=50)

def func1():
time.sleep(3)
b.wait()
print('Working from func1')
return

def func2():
time.sleep(5)
b.wait()
print('Working from func2')
return

if __name__ == '__main__':
Thread(target = func1).start()
Thread(target = func2).start()

最佳答案

您可以使用信号量模拟屏障。看一眼: Implementing an N process barrier using semaphores

问题是它没有超时参数,可能使用了Conditions ...

import time
from threading import Thread,Semaphore

class Barrier:
def __init__(self, n):
self.n = n
self.count = 0
self.mutex = Semaphore(1)
self.barrier = Semaphore(0)

def wait(self):
self.mutex.acquire()
self.count = self.count + 1
self.mutex.release()
if self.count == self.n: self.barrier.release()
self.barrier.acquire()
self.barrier.release()

b = Barrier(2)

def func1():
time.sleep(3)
#
b.wait()
#
print('Working from func1')
return

def func2():
time.sleep(5)
#
b.wait()
#
print('Working from func2')
return

if __name__ == '__main__':
Thread(target = func1).start()
Thread(target = func2).start()

关于python - 在Python2.7中实现Barrier,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/26622745/

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