java - 如何以编程方式配置 MessageDispatcherServlet

Question

我正在尝试学习 spring-ws 并从本教程开始: http://spring.io/guides/gs/producing-web-service/#initial .

我现在想做的是通过以编程方式配置应用程序，在非嵌入式 servlet 容器上启动服务。

我对如何在没有 web.xml 的情况下设置 Message Dispatcher Servlet 感到困惑。我想做的是实现 WebApplicationInitializer 接口(interface)的方法 onStartup(ServletContext servletContext)。

public class ServerInitializer  implements WebApplicationInitializer{

    public void onStartup(ServletContext servletContext) throws ServletException {

        AnnotationConfigWebApplicationContext context = new AnnotationConfigWebApplicationContext();
        context.setConfigLocation(WebServiceConfig.class.getName());
        servletContext.addListener(new ContextLoaderListener(context));

        MessageDispatcherServlet servlet = new MessageDispatcherServlet();
        servlet.setApplicationContext(context);
        servlet.setTransformWsdlLocations(true);


        // Create dispatcher for named context
        ServletRegistration.Dynamic dispatcherServlet = servletContext.addServlet("DispatcherServlet", servlet);

        // Load on startup
        dispatcherServlet.setLoadOnStartup(1);

        // Add URL mapping for dispatcher
        dispatcherServlet.addMapping("/*");


    }

}

但是，当我将它部署到 tomcat 时，我使用 SOAP UI(正在处理教程示例)发送的请求永远不会被映射

Answer 1

这就是我最终实现它的方式:

public class WebServiceInitializer implements WebApplicationInitializer {

    private static final String ACTIVE_PROFILE = "production";

    /**
     * Registers and loads on startup MessageDispatcherServlet for the SOAP messages
     */
    @Override
    public void onStartup(ServletContext servletContext) throws ServletException {

        AnnotationConfigWebApplicationContext context = new AnnotationConfigWebApplicationContext();

        // @EnableWs, @Configuration, @ComponentScan
        context.setConfigLocation(WebServiceBeans.class.getName());
        context.getEnvironment().setActiveProfiles(ACTIVE_PROFILE);

        // use MessageDispatcherServlet instead of standard DispatcherServlet for SOAP messages
        MessageDispatcherServlet servlet = new MessageDispatcherServlet();
        servlet.setContextClass(AnnotationConfigWebApplicationContext.class);
        servlet.setApplicationContext(context);
        servlet.setTransformWsdlLocations(true);

        // register MessageDispatcherServlet as Web Service entry point
        final ServletRegistration.Dynamic dispatcher = servletContext.addServlet("MessageDispatcherServlet",
                servlet);

        dispatcher.setLoadOnStartup(1);
        dispatcher.addMapping("/*");
    }

编辑://添加了正确的方法来执行此操作，之前的答案有很多冗余。