python - python中获取如下模式字符串的方法

Question

我正在使用 tylertreat/BigQuery-Python 从 BigQuery 获取表列表下面的代码在这里，

class get_Tables:
    def GET(self,r):
          web.header('Access-Control-Allow-Origin',      '*')
          web.header('Access-Control-Allow-Credentials', 'true')
          tables = []
          datasetID = web.input().dataSetID
          client = get_client(project_id, service_account=service_account,
                            private_key_file=key, readonly=True)
          result  = client._get_all_tables(datasetID,cache=False)
          tablesWithDetails =    result["tables"]
          for inditable in tablesWithDetails:
              tables.append(inditable["id"])
          print(json.dumps(tables))
          return json.dumps(tables)

上面的方法返回一个这样的JSON，

["thematic-scope-112013:Demo.Airport_Traffic", "thematic-scope-112013:Demo.Alcohol_Consumption", "thematic-scope-112013:Demo.Flight_paths", "thematic-scope-112013:Demo.GDP_Country_Wise", "thematic-scope-112013:Demo.like_data", "thematic-scope-112013:Demo.medicare_cost"]

但我只想要没有项目和数据集名称，

获取以下格式的模式或正则表达式是什么，

["Airport_Traffic", "Alcohol_Consumption", "Flight_paths", "GDP_Country_Wise", "like_data", "medicare_cost"]

Answer 1

不需要正则表达式，只需一个拆分方法就足够了。即，根据点拆分每个列表项，然后从该拆分列表中获取最后一个元素。

[i.split('.')[-1] for i in data]

示例:

>>> data =  ["thematic-scope-112013:Demo.Airport_Traffic", "thematic-scope-112013:Demo.Alcohol_Consumption", "thematic-scope-112013:Demo.Flight_paths", "thematic-scope-112013:Demo.GDP_Country_Wise", "thematic-scope-112013:Demo.like_data", "thematic-scope-112013:Demo.medicare_cost"]
>>> [i.split('.')[-1] for i in data]
['Airport_Traffic', 'Alcohol_Consumption', 'Flight_paths', 'GDP_Country_Wise', 'like_data', 'medicare_cost']