python - 如何验证每个列表是否包含一个公共(public)号码？

Question

a = [1,2,3]
b = [0,1,0]
c = [5,1,5]

if set(a)&set(b)&set(c) is True:
    print("aa")
else:
    print('ss')

每个列表都包含数字 1 所以我希望它打印 aa 但它打印 ss 即使我将 True 更改为 错误。

Answer 1

删除 is True

a=[1,2,3]
b=[0,1,0]
c=[5,1,5]
if set(a)&set(b)&set(c):
    print("aa")
else:
    print('ss')

set(a)&set(b)&set(c)返回 set([1])这不是 True .